제출 #610575

#제출 시각아이디문제언어결과실행 시간메모리
610575l_rehoValley (BOI19_valley)C++14
23 / 100
611 ms77572 KiB
#include<bits/stdc++.h> using namespace std; #define ll long long int N, S, Q, E; vector<vector<pair<int, ll>>> graph; vector<int> shops; vector<pair<int, int>> edges; vector<int> tin; vector<int> tout; map<int, bool> isShop; vector<ll> dist; vector<ll> dp; vector<vector<pair<int, ll>>> up; int timer = 0; int l = 0; void dfs(int curr, int p){ tin[curr] = timer++; vector<pair<int, ll>> adj = graph[curr]; for(pair<int, ll> a : adj){ if(a.first == p) continue; dfs(a.first, curr); } tout[curr]=timer++; } bool inst(int a, int b){ return tin[a] <= tin[b] && tout[a] >= tout[b]; } int cnt = 0; // dist[E][R] + min(dist[E][V] - dist[E][W]*2) // per ogni W posso precalcolare void bfs(int root){ queue<int> q; q.push(root); dist[root] = 0; while(!q.empty()){ int node = q.front(); q.pop(); vector<pair<int, ll>> adj = graph[node]; for(pair<int, ll> a : adj){ if(dist[a.first] != LLONG_MAX) continue; dist[a.first] = dist[node] + a.second; q.push(a.first); } } } ll precompute(int curr, int parent){ vector<pair<int, ll>> adj = graph[curr]; if(isShop[curr]) dp[curr] = dist[curr]; for(pair<int, ll> p : adj){ if(p.first == parent) continue; ll ret = precompute(p.first, curr); dp[curr] = min(dp[curr], ret); } return dp[curr]; } void binaryLifting(int curr, int p){ vector<pair<int, ll>> adj = graph[curr]; up[curr][0] = {p, min(dp[curr], dp[p])}; for(int i = 1; i <= l; i++){ pair<int, ll> upper = up[up[curr][i-1].first][i-1]; up[curr][i] = {upper.first, min(upper.second, up[curr][i-1].second)}; } for(pair<int, ll> a : adj){ if(a.first == p) continue; binaryLifting(a.first, curr); } } void solve(){ cin>>N>>S>>Q>>E; graph.assign(N+1, vector<pair<int, ll>>()); shops.assign(S, 0); tin.assign(N+1, 0); tout.assign(N+1, 0); edges.assign(N-1, pair<int, int>()); dist.assign(N+1, LLONG_MAX); dp.assign(N+1, LLONG_MAX); up.assign(N+1, vector<pair<int, ll>>(31, {0, LLONG_MAX})); l = ceil(log2(N+1)); for(int i = 0; i < N-1; i++){ int a, b, c; cin>>a>>b>>c; edges[i] = {a, b}; graph[a].push_back({b, c}); graph[b].push_back({a, c}); } for(int i = 0; i < S; i++){ cin>>shops[i]; isShop[shops[i]] = true; } dfs(E, -1); bfs(E); precompute(E, -1); for(int i = 1; i <= N; i++){ dp[i] = dp[i] - 2*dist[i]; } binaryLifting(E, E); for(int q = 0; q < Q; q++){ int a, b; cin>>a>>b; a--; // eliminiamo l'edge ad indice a pair<int, int> e = edges[a]; // mi serve l'estremo più distante da E int e1 = e.first; int e2 = e.second; bool test1 = inst(e1, e2); int d = test1 ? e2 : e1; if(!inst(d, b)){ cout<<"escaped"<<endl; continue; } // devo sfruttare il precalcolo if(N == S){ cout<<0<<endl; continue; } // adesso si dovrebbe fare il binary lifting per individuare il miglior // w tale per cui dist[E][V] - dist[E][W]*2 è minima // come posso fare binary lifting int u = b; ll ans = LLONG_MAX; for(int i = l; i >= 0; i--){ if(inst(d, up[u][i].first)){ ans = min(ans, up[u][i].second); u = up[u][i].first; } } if(u != d) ans = min(ans, up[u][0].second); if(ans == LLONG_MAX) cout<<"oo"<<endl; else cout<<ans+dist[b]<<endl; } } int main(){ solve(); return 0; }
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