제출 #607293

#제출 시각아이디문제언어결과실행 시간메모리
607293Koosha_mv자리 배치 (IOI18_seats)C++14
33 / 100
1188 ms69440 KiB
#include "seats.h" #include <bits/stdc++.h> using namespace std; #define dbgv(v) cout<<#v<<" = "; f(i,0,int(v.size())) cout<<v[i]<<" "; cout<<endl #define dbga(a,x,y) cout<<#a<<" = "; f(i,x,y) cout<<a[i]<<" "; cout<<endl #define erorp(x) cout<<#x<<"={"<<x.F<<" , "<<x.S<<"}"<<endl #define eror(x) cout<<#x<<'='<<(x)<<endl #define f_(i,a,b) for(int i=a;i>=b;i--) #define f(i,a,b) for(int i=a;i<b;i++) #define nb(x) __builtin_popcount(x) #define all(v) v.begin(),v.end() #define bit(n,k) (((n)>>(k))&1) #define maxm(a,b) a=max(a,b) #define minm(a,b) a=min(a,b) #define lst(x) x[x.size()-1] #define sz(x) int(x.size()) #define mp make_pair #define ll long long #define pb push_back #define S second #define F first const int N=1e6+99; int n,m,a[N],lz[N<<2]; pair<int,int> seg[N<<2]; vector<int> A,B; pair<int,int> operator + (pair<int,int> A,pair<int,int> B){ if(A.F==B.F) A.S+=B.S; if(A.F<=B.F) return A; return B; } void upd(int id){ seg[id]=seg[id<<1]+seg[id<<1|1]; } void shift(int id){ lz[id<<1]+=lz[id]; lz[id<<1|1]+=lz[id]; seg[id<<1].F+=lz[id]; seg[id<<1|1].F+=lz[id]; lz[id]=0; } void build(int id=1,int l=0,int r=n){ if(l+1==r){ seg[id]=mp(0,1); return ; } int mid=(l+r)>>1; build(id<<1,l,mid); build(id<<1|1,mid,r); upd(id); } void add(int L,int R,int val,int id=1,int l=0,int r=n){ if(r<=L || R<=l) return ; if(L<=l && r<=R){ lz[id]+=val; seg[id].F+=val; return ; } int mid=(l+r)>>1; shift(id); add(L,R,val,id<<1,l,mid); add(L,R,val,id<<1|1,mid,r); upd(id); } void Add(int l,int r,int val){ if(r<l) swap(l,r); add(l,r,val); } void updcell(int x,int val){ Add(a[x-1],a[x],-1); Add(a[x],a[x+1],-1); a[x]=val; Add(a[x-1],a[x],+1); Add(a[x],a[x+1],+1); } void give_initial_chart(int _n, int _m,vector<int> _A,vector<int> _B) { n=_n,m=_m; A=_A,B=_B; swap(n,m); swap(A,B); f(i,0,n) A[i]++,a[A[i]]=i; a[0]=n,a[n+1]=n; build(); f(i,0,n+1){ Add(a[i],a[i+1],1); } } int swap_seats(int u, int v) { //eror(A[u]); //eror(A[v]); updcell(A[u],v); updcell(A[v],u); swap(A[u],A[v]); return seg[1].S*(seg[1].F==2); } /* 1 4 1 0 1 0 0 0 3 0 2 0 0 1 4 4 0 0 0 1 0 2 0 3 0 1 0 3 1 3 1 2 */
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