제출 #605471

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
605471		Plurm	Uplifting Excursion (BOI22_vault)	C++11	5 / 100	5051 ms	8792 KiB

vault

#include <bits/stdc++.h>
using namespace std;

template <typename T> class negarr {
private:
  vector<T> data;
  int n;

public:
  negarr(int n) : n(n) { data.resize(2 * n + 1, 0); }
  void reset() { fill(data.begin(), data.end(), -1000000000); }
  inline T &operator[](int i) { return data[i + n]; }
};

class pstate {
public:
  int x, y;
  pstate(int x, int y) : x(x), y(y) {}
  friend bool operator<(const pstate &a, const pstate &b) {
    return a.x + a.y < b.x + b.y;
  }
};
class nstate {
public:
  int x, y;
  nstate(int x, int y) : x(x), y(y) {}
  friend bool operator<(const nstate &a, const nstate &b) {
    return a.y - a.x < b.y - b.x;
  }
};
int main() {
  int m;
  long long l;
  cin >> m >> l;
  const int BOUND = m * (m + 1) / 2 * 100;
  negarr<int> a(m), knapsack(BOUND);
  if (l > BOUND || l < -BOUND) {
    printf("impossible\n");
    return 0;
  }
  knapsack.reset();
  knapsack[0] = 0;
  for (int i = -m; i <= m; i++) {
    cin >> a[i];
    if (i == 0) {
      for (int id = -BOUND; id <= BOUND; id++) {
        knapsack[id] += a[i];
      }
    } else if (abs(i) > 20) {
      negarr<int> tmp(BOUND);
      tmp.reset();
      if (i > 0) {
        vector<vector<nstate>> pq(i);
        for (int id = -BOUND; id <= BOUND; id++) {
          int mod = id % i;
          if (mod < 0)
            mod += i;
          pq[mod].reserve(2 * BOUND / i + 5);
        }
        for (int id = -BOUND; id <= BOUND; id++) {
          int mod = id % i;
          if (mod < 0)
            mod += i;
          int xx = (id + BOUND) / i;
          while (!pq[mod].empty() && xx - pq[mod].front().x > a[i]) {
            pop_heap(pq[mod].begin(), pq[mod].end());
            pq[mod].pop_back();
          }
          while (!pq[mod].empty() &&
                 pq[mod].front() < nstate(xx, knapsack[id])) {
            pop_heap(pq[mod].begin(), pq[mod].end());
            pq[mod].pop_back();
          }
          pq[mod].push_back({xx, knapsack[id]});
          push_heap(pq[mod].begin(), pq[mod].end());
          if (!pq[mod].empty()) {
            nstate t = pq[mod].front();
            tmp[id] = max(tmp[id], t.y - t.x + xx);
          }
        }
      } else if (i < 0) {
        vector<vector<pstate>> pq(-i);
        for (int id = -BOUND; id <= BOUND; id++) {
          int mod = id % (-i);
          if (mod < 0)
            mod += (-i);
          pq[mod].reserve(2 * BOUND / (-i) + 5);
        }
        for (int id = BOUND; id >= -BOUND; id--) {
          int mod = id % (-i);
          if (mod < 0)
            mod += (-i);
          int xx = (id + BOUND) / (-i);
          while (!pq[mod].empty() && pq[mod].front().x - xx > a[i]) {
            pop_heap(pq[mod].begin(), pq[mod].end());
            pq[mod].pop_back();
          }
          while (!pq[mod].empty() &&
                 pq[mod].front() < pstate(xx, knapsack[id])) {
            pop_heap(pq[mod].begin(), pq[mod].end());
            pq[mod].pop_back();
          }
          pq[mod].push_back({xx, knapsack[id]});
          push_heap(pq[mod].begin(), pq[mod].end());
          if (!pq[mod].empty()) {
            pstate t = pq[mod].front();
            knapsack[id] = max(knapsack[id], t.y + t.x - xx);
          }
        }
      }
      for (int id = -BOUND; id <= BOUND; id++) {
        knapsack[id] = max(knapsack[id], tmp[id]);
      }
    } else {
      for (int rep = 0; rep < a[i]; rep++) {
        negarr<int> tmp(BOUND);
        tmp.reset();
        for (int id = -BOUND; id <= BOUND; id++) {
          if (-BOUND <= id + i && id + i <= BOUND)
            tmp[id + i] = max(tmp[id + i], knapsack[id] + 1);
        }
        for (int id = -BOUND; id <= BOUND; id++) {
          knapsack[id] = max(knapsack[id], tmp[id]);
        }
      }
    }
  }
  if (knapsack[l] >= 0)
    printf("%d\n", knapsack[l]);
  else
    printf("impossible\n");
  return 0;
}

• Subtask 1: 5 / 5
• Subtask 2: 0 / 15
• Subtask 3-1: 0 / 10
• Subtask 3-2: 0 / 10
• Subtask 4-1: 0 / 10
• Subtask 4-2: 0 / 10
• Subtask 5-1: 0 / 10
• Subtask 5-2: 0 / 10
• Subtask 6-1: 0 / 10
• Subtask 6-2: 0 / 10