Submission #603942

#TimeUsernameProblemLanguageResultExecution timeMemory
603942Sam_a17Connecting Supertrees (IOI20_supertrees)C++14
0 / 100
4 ms4948 KiB
#include <bits/stdc++.h> using namespace std; #define sz(x) (int((x).size())) #define len(x) (int)x.length() #define all(x) (x).begin(), (x).end() #define rall(x) (x).rbegin(), (x).rend() #define dbg(x) cout << #x << " " << x << endl; #define uniq(x) x.resize(unique(all(x)) - x.begin()); #define pb push_back #define ld long double #define ll long long void build(std::vector<std::vector<int>> p); const int N = 2e5 + 10, M = 1e3 + 10; vector<int> cycles[N]; int par[N], sz[N], comp[N], c = 1; int comp2[N]; int find(int a) { if(a != par[a]) { par[a] = find(par[a]); } return par[a]; } int same(int a, int b) { if(find(a) == find(b)) { return 1; } else { return 0; } } int merge(int a, int b) { a = find(a), b = find(b); if(a == b) { return 0; } if(sz[a] < sz[b]) { swap(a, b); } par[b] = a, sz[a] += sz[b]; return 1; } int construct(std::vector<std::vector<int>> p) { int n = p.size(); for(int i = 0; i < n; i++) { par[i] = i, sz[i] = 1; for(int j = 0; j < n; j++) { if(p[i][j] == 3) { return 0; } } } vector<bool> vis(n); vector<vector<int>> answ(n, vector<int> (n, 0)); vector<int> cycle; for(int i = 0; i < n; i++) { if(vis[i]) { continue; } queue<int> q; q.push(i); vis[i] = 1; vector<int> curr; while(!q.empty()) { int u = q.front(); q.pop(); curr.push_back(u); for(int j = 0; j < n; j++) { if(!vis[j] && p[u][j] == 1) { vis[j] = 1; q.push(j); } } } int m = sz(curr); for(int j = 0; j < m; j++) { comp[curr[j]] = c; } cycle.push_back(curr[0]); for(int j = 1; j < m; j++) { answ[curr[j - 1]][curr[j]] = 1; answ[curr[j]][curr[j - 1]] = 1; } c++; } for(int i = 0; i < n; i++) { vis[i] = false; } c = 1; for(auto i: cycle) { if(vis[i]) continue; queue<int> q; vector<int> curr; q.push(i), vis[i] = true; curr.push_back(i); // while(!q.empty()) { auto u = q.front(); q.pop(); for(int j = 0; j < n; j++) { if(!vis[j] && p[u][j] == 2) { vis[j] = 1, curr.push_back(j); q.push(j); } } } int m = sz(curr); for(int j = 0; j < m; j++) { answ[curr[j]][curr[(j + 1) % m]] = 1; answ[curr[(j + 1) % m]][curr[j]] = 1; } } build(answ); return 1; }
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