답안 #602206

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
602206 2022-07-22T17:12:45 Z inksamurai Relativnost (COCI15_relativnost) C++17
0 / 140
4000 ms 65228 KB
#include <bits/stdc++.h>

// cut here
#ifdef _MSC_VER
#include <intrin.h>
#endif
 
namespace atcoder {
 
namespace internal {
 
int ceil_pow2(int n) {
    int x = 0;
    while ((1U << x) < (unsigned int)(n)) x++;
    return x;
}
 
int bsf(unsigned int n) {
#ifdef _MSC_VER
    unsigned long index;
    _BitScanForward(&index, n);
    return index;
#else
    return __builtin_ctz(n);
#endif
}
 
}  // namespace internal
 
}  // namespace atcoder
 
 
namespace atcoder {
 
template <class S, S (*op)(S, S), S (*e)()> struct segtree {
  public:
    segtree() : segtree(0) {}
    segtree(int n) : segtree(std::vector<S>(n, e())) {}
    segtree(const std::vector<S>& v) : _n(int(v.size())) {
        log = internal::ceil_pow2(_n);
        size = 1 << log;
        d = std::vector<S>(2 * size, e());
        for (int i = 0; i < _n; i++) d[size + i] = v[i];
        for (int i = size - 1; i >= 1; i--) {
            update(i);
        }
    }
 
    void set(int p, S x) {
        assert(0 <= p && p < _n);
        p += size;
        d[p] = x;
        for (int i = 1; i <= log; i++) update(p >> i);
    }
 
    S get(int p) {
        assert(0 <= p && p < _n);
        return d[p + size];
    }
 
    S prod(int l, int r) {
        assert(0 <= l && l <= r && r <= _n);
        S sml = e(), smr = e();
        l += size;
        r += size;
 
        while (l < r) {
            if (l & 1) sml = op(sml, d[l++]);
            if (r & 1) smr = op(d[--r], smr);
            l >>= 1;
            r >>= 1;
        }
        return op(sml, smr);
    }
 
    S all_prod() { return d[1]; }
 
    template <bool (*f)(S)> int max_right(int l) {
        return max_right(l, [](S x) { return f(x); });
    }
    template <class F> int max_right(int l, F f) {
        assert(0 <= l && l <= _n);
        assert(f(e()));
        if (l == _n) return _n;
        l += size;
        S sm = e();
        do {
            while (l % 2 == 0) l >>= 1;
            if (!f(op(sm, d[l]))) {
                while (l < size) {
                    l = (2 * l);
                    if (f(op(sm, d[l]))) {
                        sm = op(sm, d[l]);
                        l++;
                    }
                }
                return l - size;
            }
            sm = op(sm, d[l]);
            l++;
        } while ((l & -l) != l);
        return _n;
    }
 
    template <bool (*f)(S)> int min_left(int r) {
        return min_left(r, [](S x) { return f(x); });
    }
    template <class F> int min_left(int r, F f) {
        assert(0 <= r && r <= _n);
        assert(f(e()));
        if (r == 0) return 0;
        r += size;
        S sm = e();
        do {
            r--;
            while (r > 1 && (r % 2)) r >>= 1;
            if (!f(op(d[r], sm))) {
                while (r < size) {
                    r = (2 * r + 1);
                    if (f(op(d[r], sm))) {
                        sm = op(d[r], sm);
                        r--;
                    }
                }
                return r + 1 - size;
            }
            sm = op(d[r], sm);
        } while ((r & -r) != r);
        return 0;
    }
 
  private:
    int _n, size, log;
    std::vector<S> d;
 
    void update(int k) { d[k] = op(d[2 * k], d[2 * k + 1]); }
};
 
}  // namespace atcoder
// cut here 
#define int ll
using namespace std;
#define rep(i,n) for(int i=0;i<n;i++)
#define rng(i,c,n) for(int i=(c);i<n;i++)
#define per(i,n) for(int i=n-1;i>=0;i--)
#define fi first
#define se second
#define sz(a) (int)a.size()
#define vec(...) vector<__VA_ARGS__>
#define _3aFGabX ios::sync_with_stdio(0),cin.tie(0)
typedef long long ll;
using pii=pair<int,int>;
using vi=vector<int>;
void print(){cout<<'\n';}
template<class h,class...t>
void print(const h&v,const t&...u){cout<<v<<' ',print(u...);}
// e

const int _c=21;
const int mod=10007;

struct dat{
	int dp[_c+2]{0};
};

dat op(dat l,dat r){
	dat res;
	rep(i,_c){
		rep(j,_c){
			int k=min(_c,i+j);
			res.dp[k]+=l.dp[i]*r.dp[j]%mod;
			res.dp[k]%=mod;
		}
	}
	return res;
} 

dat _e;

dat e(){
	return _e;
}

signed main(){
_3aFGabX;
	_e.dp[0]=1;
	int n,c;
	cin>>n>>c;
	vec(pii) a(n);
	rep(i,n){
		int v;
		cin>>v;
		a[i].fi=v;
	}
	rep(i,n){
		int v;
		cin>>v;
		a[i].se=v;
	}
	atcoder::segtree<dat,op,e> seg(n);
	rep(i,n){
		dat now;
		now.dp[0]=a[i].se%mod;
		now.dp[1]=a[i].fi%mod;
		seg.set(i,now);
	}
	int q;
	cin>>q;
	// assert(q<=1000);
	rep(_,q)
	{
		int i,_a,_b;
		cin>>i>>_a>>_b;
		i-=1;
		a[i]={_a,_b};
		dat now;
		now.dp[0]=a[i].se%mod;
		now.dp[1]=a[i].fi%mod;
		// print(a[i].fi,a[i].se);
		seg.set(i,now);
		// print(seg.prod(0,2).dp[0],seg.prod(0,2).dp[2]);
		dat res=seg.prod(0,n);
		int ans=0;
		rng(i,c,_c+1){
			// cout<<res.dp[i]<<" ";
			ans+=res.dp[i]%mod;
			ans%=mod;
		}
		cout<<ans<<"\n";
		// break;
	}
}
# 결과 실행 시간 메모리 Grader output
1 Incorrect 59 ms 852 KB Output isn't correct
2 Incorrect 58 ms 852 KB Output isn't correct
3 Incorrect 49 ms 724 KB Output isn't correct
4 Execution timed out 4100 ms 34168 KB Time limit exceeded
5 Execution timed out 4091 ms 64240 KB Time limit exceeded
6 Execution timed out 4103 ms 65228 KB Time limit exceeded
7 Execution timed out 4069 ms 36180 KB Time limit exceeded
8 Execution timed out 4078 ms 65220 KB Time limit exceeded
9 Execution timed out 4090 ms 61980 KB Time limit exceeded
10 Execution timed out 4088 ms 61284 KB Time limit exceeded