이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<bits/stdc++.h>
#pragma GCC optimize ("O3")
#pragma GCC target ("sse4")
#define MAXN 200007
using namespace std;
const long long inf=1e16;
int n,d;
long long t,a[MAXN],b[MAXN],poss[MAXN];
long long dp[MAXN][2],cost;
void solve(int l,int r,int optl,int optr,int k){
if(l>r)return;
int mid=(l+r)/2,opt=0;
dp[mid][k%2]=inf; cost=0;
for(int i=mid;i<=optr;i++){
if(poss[i]>=mid)cost++;
if(dp[i+1][(k-1)%2]+cost<dp[mid][k%2]){
dp[mid][k%2]=dp[i+1][(k-1)%2]+cost;
opt=i;
}
}
solve(l,mid-1,optl,opt,k);
solve(mid+1,r,opt,optr,k);
}
int power[20],lg[MAXN];
long long mind[MAXN][20];
bool li[MAXN][20];
void calc(){
power[0]=1; lg[1]=0;
for(int i=1;i<20;i++)power[i]=power[i-1]*2;
for(int i=2;i<=n;i++)lg[i]=lg[i/2]+1;
}
long long rmq(int i,int j){
if(j==0)return b[i];
if(li[i][j])return mind[i][j];
li[i][j]=true;
mind[i][j]=min(rmq(i,j-1),rmq(i+power[j-1],j-1));
return mind[i][j];
}
long long getmin(int l,int r){
return min( rmq(l,lg[r-l+1]) , rmq(r-power[lg[r-l+1]]+1,lg[r-l+1]) );
}
int main(){
cin>>n>>d>>t;
for(int i=1;i<=n;i++){
cin>>a[i];
b[i]=a[i]-i;
}
calc();
for(int i=1;i<=n;i++){
int l=0,r=i+1,mid;
while(l+1<r){
mid=(l+r)/2;
if(min(getmin(mid,i)+i,a[i])<=t){
l=mid;
}else{
r=mid;
}
}
poss[i]=l;
}
dp[n+1][0]=0;
for(int i=1;i<=n;i++){
dp[i][0]=inf;
}
for(int i=1;i<=d+1;i++){
dp[n+1][i%2]=inf;
solve(1,n,1,n,i);
}
cout<<dp[1][(d+1)%2]<<"\n";
return 0;
}
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