# | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
---|---|---|---|---|---|---|---|
601177 | CSQ31 | Uplifting Excursion (BOI22_vault) | C++17 | 1319 ms | 524288 KiB |
이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
#define all(a) a.begin(),a.end()
#define owo ios_base::sync_with_stdio(0);cin.tie(0);
typedef long long int ll;
ll A[5000],B[5000];
unordered_map<ll,ll>val,dp;
int main()
{
int m;
ll L;
cin>>m>>L;
for(int i=-m;i<=m;i++)cin>>A[i+m];
ll ans = A[m];
/*
//subtask 2 m^4 knapsack??
//consider left and right side separately
//let ai be number of art piece i chosen
//1)atleast one of ai , a_{-i} must be 0
//2)consider only positive
//ai aj i<j
//if aj >= i and ai <= Ai-j
//do ai+=j aj-=i
//j > i
//ai <= Ai-M and aj >= M cant be both true
//a prefix p has ai>Ai-M then p+1 can be anything
//ahhhhhhhhh iterate first i such that ai <= M
for(int i=1;i<=m;i++){
}
*/
dp[0] = 0;
for(ll i=1;i<=m;i++){
ll z = 1;
vector<ll>item;
while(A[i+m]>=z){
item.push_back(z);
A[i+m]-=z;
z*=2;
}
if(A[i+m])item.push_back(A[i+m]);
for(ll x:item){
vector<array<ll,2>>upd;
for(auto y:dp)upd.push_back({x*i+y.first,y.second+x});
for(auto x:upd)dp[x[0]] = max(dp[x[0]],x[1]);
}
}
if(dp.find(L) == dp.end())cout<<"impossible";
else cout<<dp[L]+A[m]<<'\n';
}
컴파일 시 표준 에러 (stderr) 메시지
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