이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
// #pragma GCC optimize ("Ofast,unroll-loops")
// #pragma GCC target ("avx2")
using namespace std;
typedef long long ll;
typedef pair<int, int> pp;
#define er(args ...) cerr << __LINE__ << ": ", err(new istringstream(string(#args)), args), cerr << endl
#define per(i,r,l) for(int i = (r); i >= (l); i--)
#define rep(i,l,r) for(int i = (l); i < (r); i++)
#define all(x) begin(x), end(x)
#define sz(x) (int)(x).size()
#define pb push_back
#define ss second
#define ff first
void err(istringstream *iss){}template<typename T,typename ...Args> void err(istringstream *iss,const T &_val, const Args&...args){string _name;*iss>>_name;if(_name.back()==',')_name.pop_back();cerr<<_name<<" = "<<_val<<", ",err(iss,args...);}
void IOS(){
cin.tie(0) -> sync_with_stdio(0);
// #ifndef ONLINE_JUDGE
// freopen("in.in", "r", stdin);
// freopen("out.out", "w", stdout);
// #endif
}
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const ll mod = 1e9 + 7, maxn = 1e6 + 5, lg = 22, inf = ll(1e9) + 5;
ll pw(ll a,ll b,ll md=mod){if(!b)return 1;ll k=pw(a,b>>1ll);return k*k%md*(b&1ll?a:1)%md;}
pp seg[maxn<<2];
int laz[maxn<<2];
void updNode(int x, int k){
seg[x].ff += k, laz[x] += k;
}
void shift(int x){
if(laz[x]){
updNode(x<<1, laz[x]);
updNode(x<<1|1, laz[x]);
laz[x] = 0;
}
}
pp get(){
return seg[1];
}
int get(int i, int x = 1, int lx = 0, int rx = maxn){
if(lx + 1 == rx) return seg[x].ff;
int mid = (lx + rx)>>1;
shift(x);
if(i < mid) return get(i, x<<1, lx, mid);
return get(i, x<<1|1, mid, rx);
}
void upd(int l, int r, int k, int x = 1, int lx = 0, int rx = maxn){
if(l <= lx && r >= rx){
updNode(x, k);
return;
}
shift(x);
int mid = (lx + rx)>>1;
if(l < mid) upd(l, r, k, x<<1, lx, mid);
if(mid < r) upd(l, r, k, x<<1|1, mid, rx);
seg[x] = max(seg[x<<1], seg[x<<1|1]);
}
vector<int> adj[maxn];
int par[maxn], h[maxn], st[maxn], en[maxn], tt, inv[maxn];
bool vis[maxn];
void dfs(int r){
inv[tt] = r, st[r] = tt++, vis[r] = true;
for(int c: adj[r]) h[c] = h[r] + 1, dfs(c);
en[r] = tt;
}
int main(){ IOS();
int n, d, t; cin >> n >> d >> t;
vector<int> a(n), e(n);
rep(i,0,n) cin >> a[i], e[i] = t - a[i] + i;
vector<bool> is(n);
int mx = -1, ans = 0;
rep(i,0,n){
er(a[i]);
if(a[i] > t) {
if(mx < i) ans++;
else is[i] = true, er(i);
}
mx = max(mx, e[i]);
}
vector<int> stk;
per(i,n-1,0){
if(is[i]){
par[i] = -1;
if(sz(stk)) par[i] = stk.back(), adj[par[i]].pb(i);
stk.pb(i);
}else{
while(sz(stk) && stk.back() <= e[i]) stk.pop_back();
}
}
rep(i,0,n) {
if(!vis[i]) h[i] = 1, dfs(i);
upd(st[i], st[i]+1, h[i]);
}
while(d--){
auto[hh, id] = get();
if(hh <= 0) break;
int r = inv[id];
while(r + 1 && vis[r]){
ans++;
int H = get(st[r], st[r]+1);
upd(st[r], en[r], -H);
vis[r] = false, r = par[r];
}
}
cout << n - ans << endl;
return 0;
}
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