이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include "jumps.h"
using namespace std;
const int MAX_N = 2e5 + 5;
int N;
int H[MAX_N];
int L[MAX_N], R[MAX_N], J1[MAX_N][20], J2[MAX_N][20], mx[MAX_N][20];
int table[MAX_N][20];
void init(int n, vector <int> h) {
N = n;
for(int i = 1; i <= N; i++) {
H[i] = h[i - 1];
table[i][0] = H[i];
}
H[0] = H[N + 1] = N + 1;
for(int j = 1; j < 20; j++) {
for(int i = 1; i + (1<<j) - 1 <= N; i++) {
table[i][j] = max(table[i][j - 1], table[i + (1<<(j - 1))][j - 1]);
}
}
stack <int> stk;
stk.push(0);
for(int i = 1; i <= N; i++) {
while(!stk.empty() and H[stk.top()] < H[i]) {
stk.pop();
}
L[i] = stk.top();
stk.push(i);
}
while(!stk.empty()) {
stk.pop();
}
stk.push(N + 1);
for(int i = N; i >= 1; i--) {
while(!stk.empty() and H[stk.top()] < H[i]) {
stk.pop();
}
R[i] = stk.top();
stk.push(i);
}
L[N + 1] = 0;
R[0] = N + 1;
for(int i = 0; i <= N + 1; i++) {
if(H[L[i]] > H[R[i]]) {
J1[i][0] = L[i];
J2[i][0] = R[i];
}
else {
J1[i][0] = R[i];
J2[i][0] = L[i];
}
mx[i][0] = max(L[i], R[i]);
}
for(int j = 1; j < 20; j++) {
for(int i = 0; i <= N + 1; i++) {
J1[i][j] = J1[J1[i][j - 1]][j - 1];
J2[i][j] = J2[J2[i][j - 1]][j - 1];
mx[i][j] = mx[mx[i][j - 1]][j - 1];
}
}
}
int get_max(int l, int r) {
if(l > r) {
return 0;
}
int j = log2(r - l + 1);
return max(table[l][j], table[r - (1<<j) + 1][j]);
}
int minimum_jumps(int A, int B, int C, int D) {
A++, B++, C++, D++;
int lft = get_max(A, B), mid = get_max(B + 1, C - 1), rgh = get_max(C, D);
if(max(lft, mid) > rgh) {
return -1;
}
if(lft > mid) {
return 1;
}
int l = A, r = B, now = B;
while(l <= r) {
int m = (l + r) / 2;
if(H[m] < mid) {
r = m - 1;
now = m;
}
else {
l = m + 1;
}
}
int ans = 0;
for(int i = 19; i >= 0; i--) {
if(H[J1[now][i]] < rgh and mx[now][i] < C) {
now = J1[now][i];
ans += (1<<i);
}
}
if(mx[now][0] >= C) {
ans++;
now = mx[now][0];
}
else {
for(int i = 19; i >= 0; i--) {
if(H[J1[now][i]] < rgh and J2[now][i] < C) {
now = J2[now][i];
ans += (1<<i);
}
}
ans++;
now = J1[now][0];
}
if(C <= now and now <= D) {
return ans;
}
return -1;
}
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