제출 #598348

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
598348		bojackduy	Knapsack (NOI18_knapsack)	C++14	29 / 100	56 ms	1920 KiB

knapsack

#include<iostream>
#include<queue>
#include<stack>
#include<algorithm>
#include<string.h>
#define int long long
#define size() size() * 1ll 
#define all(x) (x).begin(), (x).end()
#define allr(x, sz) (x) + 1, (x) + 1 + sz
#define pb push_back
#define pii pair<int,int>
#define fi first
#define se second
#define MASK(x) (1LL<<(x))
#define BIT(x,i) (((x)>>(i))&1)
#define numbit(x) __builtin_popcountll(x)

using namespace std;

const int N = 1e5 + 1;
const int M = 2e3 + 1;
const long long mod = 1e9 + 7;
const long long oo = 1e18 + 7;

typedef vector<int> vi;
typedef vector<pii> vii;
typedef long long ll;

template<class t>
bool mini(t &x,t y) {
    if (y < x) {
       x = y;
       return 1;
    }
return 0;
}
template<class t>
bool maxi(t &x,t y) {
    if (x < y) {
       x = y;
       return 1;
    }
return 0;
}
void file() {
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    // freopen(task".inp", "r", stdin);
    // freopen(task".out", "w", stdout);
return ;
}

int n, m;
int v[N], w[N], k[N];
int dp[N][M];
void DP(int i, vi &f) {
    for (int j = w[i]; j <= m; j++) {
        int l = 1, r = min(j / w[i], k[i]);
        int vall = dp[i][j - w[i] * l] + v[i] * l;
        int valr = dp[i][j - w[i] * r] + v[i] * r;
        for (int t = 30; t; t--) {
            int midl = (l + l + r) / 3;
            int midr = (l + r + r) / 3;
            vall = dp[i][j - w[i] * midl] + v[i] * midl;
            valr = dp[i][j - w[i] * midr] + v[i] * midr;
            maxi(f[j], vall);
            maxi(f[j], valr);
            if (vall <= valr) l = midl; else r = midr;
        }
        for (int it = l; it <= r; it++) {
            maxi(f[j], dp[i][j - w[i] * it] + v[i] * it);
        }
    }
}
void solve(int test = -1) {
    cin >> m >> n;
    for (int i = 1; i <= n; i++) {
        cin >> v[i] >> w[i] >> k[i];
    }
    for (int i = 1; i <= n; i++) {
        for (int j = 0; j <= m; j++) {
            maxi(dp[i][j], dp[i - 1][j]);
        }
        
        vi f(m + 1, 0);
    
        DP(i, f);

        for (int j = w[i]; j <= m; j++) {
            maxi(dp[i][j], f[j]);
        }

        // for (int j = 0; j <= m; j++) cout << dp[i][j] << " \n"[j == m];
    }
    cout << dp[n][m];
}

int32_t main()  {
    file();
    int T = 1;
    // cin >> T;
    for (int i = 1; i <= T; i++) {
        solve(i);
    }
return 0;
}
/*
20 3
5000 15 1
100 1 3
50 1 4

WRONG
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 5000 5000 5000 5000 5000 5000
0 100 200 200 200 200 200 200 200 200 200 200 200 200 200 5000 5000 5200 5200 5200 5200
0 100 200 200 300 350 350 350 350 350 350 350 350 350 350 5000 5000 5200 5200 5300 5350

RIGHT
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 5000 5000 5000 5000 5000 5000
0 100 200 300 300 300 300 300 300 300 300 300 300 300 300 5000 5100 5200 5300 5300 5300
0 100 200 300 350 400 450 500 500 500 500 500 500 500 500 5000 5100 5200 5300 5350 5400
*/

• Subtask 1: 12 / 12
• Subtask 2: 17 / 17
• Subtask 3: 0 / 20
• Subtask 4: 0 / 24
• Subtask 5: 0 / 27