Submission #59741

#TimeUsernameProblemLanguageResultExecution timeMemory
59741Benq구슬과 끈 (APIO14_beads)C++11
28 / 100
1079 ms1024 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/tree_policy.hpp> #include <ext/pb_ds/assoc_container.hpp> using namespace std; using namespace __gnu_pbds; typedef long long ll; typedef long double ld; typedef complex<ld> cd; typedef pair<int, int> pi; typedef pair<ll,ll> pl; typedef pair<ld,ld> pd; typedef vector<int> vi; typedef vector<ld> vd; typedef vector<ll> vl; typedef vector<pi> vpi; typedef vector<pl> vpl; typedef vector<cd> vcd; template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>; #define FOR(i, a, b) for (int i=a; i<(b); i++) #define F0R(i, a) for (int i=0; i<(a); i++) #define FORd(i,a,b) for (int i = (b)-1; i >= a; i--) #define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--) #define sz(x) (int)(x).size() #define mp make_pair #define pb push_back #define f first #define s second #define lb lower_bound #define ub upper_bound #define all(x) x.begin(), x.end() const int MOD = 1000000007; const ll INF = 1e18; const int MX = 10001; int n; vpi adj[MX]; pi comb(pi ret, pi x, int len) { ret.s = max(ret.s+max(x.f,x.s),ret.f+len+x.f); ret.f += max(x.f,x.s); return ret; } pi dfs(int cur, int pre) { pi ret = {0,-MOD}; // no needed, needed for (auto a: adj[cur]) if (a.f != pre) { pi x = dfs(a.f,cur); x.s += a.s; ret = comb(ret,x,a.s); } // cout << cur << " " << ret.f << " " << ret.s << "\n"; return ret; } int main() { ios_base::sync_with_stdio(0); cin.tie(0); cin >> n; F0R(i,n-1) { int a,b,c; cin >> a >> b >> c; adj[a].pb({b,c}), adj[b].pb({a,c}); } int ans = 0; // dfs(5,0); FOR(i,1,n+1) { // cout << dfs(i,0).f << "\n"; ans = max(ans,dfs(i,0).f); } cout << ans; } /* Look for: * the exact constraints (multiple sets are too slow for n=10^6 :( ) * special cases (n=1?) * overflow (ll vs int?) * array bounds */
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