제출 #595248

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
595248		alextodoran	Treasure (different grader from official contest) (CEOI13_treasure2)	C++17	90 / 100	1 ms	468 KiB

treasure

/**
 ____ ____ ____ ____ ____
||a |||t |||o |||d |||o ||
||__|||__|||__|||__|||__||
|/__\|/__\|/__\|/__\|/__\|

**/

#include <bits/stdc++.h>
#include "treasure.h"

using namespace std;

typedef long long ll;

const int N_MAX = 100;

int N;

bool found[N_MAX + 2][N_MAX + 2];

int UL[N_MAX + 2][N_MAX + 2];
int UR[N_MAX + 2][N_MAX + 2];
int DL[N_MAX + 2][N_MAX + 2];
int DR[N_MAX + 2][N_MAX + 2];

void findTreasure(int N) {
    // Compute sum of cheaper corner
    for (int i = 1; i <= N / 2; i++) {
        for (int j = 1; j <= N / 2; j++) {
            DR[i][j] = countTreasure(i, j, N, N);
        }
    }
    for (int i = 1; i <= N / 2; i++) {
        for (int j = N / 2; j < N; j++) {
            DL[i][j] = countTreasure(i, 1, N, j);
        }
    }
    for (int i = 1; i <= N / 2; i++) {
        DL[i][N] = DR[i][1];
    }
    for (int i = N / 2; i < N; i++) {
        for (int j = 1; j <= N / 2; j++) {
            UR[i][j] = countTreasure(1, j, i, N);
        }
    }
    for (int j = 1; j <= N / 2; j++) {
        UR[N][j] = DR[1][j];
    }
    for (int i = N / 2; i < N; i++) {
        for (int j = N / 2; j < N; j++) {
            UL[i][j] = countTreasure(1, 1, i, j);
        }
    }
    for (int i = N / 2; i <= N; i++) {
        UL[i][N] = UR[i][1];
    }
    for (int j = N / 2; j <= N; j++) {
        UL[N][j] = DL[1][j];
    }
    // Compute sum of upper-left corner
    for (int i = 1; i <= N / 2 - 1; i++) {
        for (int j = N / 2; j <= N; j++) {
            UL[i][j] = DL[1][j] - DL[i + 1][j];
        }
    }
    for (int i = N / 2; i <= N; i++) {
        for (int j = 1; j <= N / 2 - 1; j++) {
            UL[i][j] = UR[i][1] - UR[i][j + 1];
        }
    }
    for (int i = 1; i <= N / 2 - 1; i++) {
        for (int j = 1; j <= N / 2 - 1; j++) {
            UL[i][j] = UL[i][N] + UL[N][j] + DR[i + 1][j + 1] - DR[1][1];
        }
    }
    for (int i = 1; i <= N; i++) {
        for (int j = 1; j <= N; j++) {
            found[i][j] = UL[i][j] - UL[i - 1][j] - UL[i][j - 1] + UL[i - 1][j - 1];
        }
    }
    for (int i = 1; i <= N; i++) {
        for (int j = 1; j <= N; j++) {
            if (found[i][j] == true) {
                Report(i, j);
            }
        }
    }
}

• Subtask 1: 90 / 100