oj.uz

답안 #59383

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
59383 2018-07-21T22:32:33 Z duality 코알라 (APIO17_koala) C++11
33 / 100
 164 ms 948 KB 
#include <bits/stdc++.h>
using namespace std;
#define pb push_back
#define mp make_pair
typedef long long int LLI;
typedef pair<int,int> pii;
typedef vector<int> vi;
typedef vector<pii> vpii;
#include "koala.h"

int B[100],R[100];
int minValue(int N, int W) {
    int i;
    for (i = 0; i < N; i++) B[i] = 0;
    B[0] = 1;
    playRound(B,R);
    for (i = 0; i < N; i++) {
        if (R[i] == 0) return i;
    }
    return 0;
}

int maxValue(int N, int W) {
    int i;
    for (i = 0; i < N; i++) B[i] = 1;
    playRound(B,R);
    int c = 0;
    for (i = 0; i < N; i++) {
        if (R[i] == 2) B[i] = 2;
        else B[i] = 0;
    }
    playRound(B,R);
    for (i = 0; i < N; i++) {
        if (R[i] == 3) c++,B[i] = 4;
        else B[i] = 0;
    }
    playRound(B,R);
    for (i = 0; i < N; i++) {
        if (R[i] == 5) B[i] = 11;
        else B[i] = 0;
    }
    playRound(B,R);
    for (i = 0; i < N; i++) {
        if (R[i] == 12) return i;
    }
}

int compare(int a,int b,int N,int W) {
    /*int i,j;
    vi poss;
    for (i = 0; i < N; i++) poss.pb(i);
    int l = 1,r = N;
    while (1) {
        for (i = 0; i < N; i++) B[i] = 0;
        int val = 1,e = N;
        for (i = 1; i <= N/poss.size(); i++) {
            int m1 = 0,m2 = 0,ee = N;
            for (j = 0; j <= N-(r-l+1); j++) {
                int x = min((W-j)/(i+1),r-l+1);
                int sum = (2*N-min(j,N-r)+1)*min(j,N-r)/2;
                sum += (2*(l-1)-(j-min(j,N-r))+1)*(j-min(j,N-r))/2;
                sum += (2*r-x+1)*x/2;
                if ((sum > m1) || ((sum == m1) && (j+x > m2))) {
                    m1 = sum,m2 = j+x;
                    ee = max(x,r-l+1-x);
                }
            }
            if (ee < e) e = ee,val = i;
        }
        //cout<<l<<","<<r<<","<<val<<","<<e<<endl;
        for (i = 0; i < poss.size(); i++) B[poss[i]] = val;//min(poss.size()-1,N/poss.size());
        playRound(B,R);
        if ((R[a] > 0) != (R[b] > 0)) return R[b] > 0;
        vi poss2;
        for (i = 0; i < poss.size(); i++) {
            if (R[a] > 0) {
                if (R[poss[i]] > 0) poss2.pb(poss[i]);
            }
            else {
                if (R[poss[i]] == 0) poss2.pb(poss[i]);
            }
        }
        if (R[a] > 0) l = r-poss2.size()+1;
        else r = l+poss2.size()-1;
        poss = poss2;
    }
    return 0;*/
    int i,j;
    i = 1;
    for (j = 0; j < N; j++) B[i] = 0;
    B[a] = B[b] = i;
    playRound(B,R);
    if ((R[a] > 0) != (R[b] > 0)) return R[b] > 0;
    i = 11;
    for (j = 0; j < N; j++) B[i] = 0;
    B[a] = B[b] = i;
    playRound(B,R);
    if ((R[a] > 0) != (R[b] > 0)) return R[b] > 0;
    i = 3;
    for (j = 0; j < N; j++) B[i] = 0;
    B[a] = B[b] = i;
    playRound(B,R);
    if ((R[a] > 0) != (R[b] > 0)) return R[b] > 0;
    i = 6;
    for (j = 0; j < N; j++) B[i] = 0;
    B[a] = B[b] = i;
    playRound(B,R);
    if ((R[a] > 0) != (R[b] > 0)) return R[b] > 0;
    return -1;
}
int greaterValue(int N, int W) {
    return compare(0,1,N,W);
}

int n,w;
int inv[100];
bool comp(int a,int b) {
    return compare(a,b,n,w);
}
void allValues(int N, int W, int *P) {
    n = N,w = N;
    if (W == 2*N) {
        // TODO: Implement Subtask 4 solution here.
        // You may leave this block unmodified if you are not attempting this
        // subtask.
    } else {
        int i;
        for (i = 0; i < N; i++) inv[i] = i;
        random_shuffle(inv,inv+N);
        sort(inv,inv+N,comp);
        for (i = 0; i < N; i++) P[inv[i]] = i+1;
    }
}

Compilation message

koala.cpp: In function 'int maxValue(int, int)':
koala.cpp:46:1: warning: control reaches end of non-void function [-Wreturn-type]
 }
 ^

Subtask #1
4.0 / 4.0

# 결과 실행 시간 메모리 Grader output
1 Correct 7 ms 376 KB Output is correct
2 Correct 7 ms 376 KB Output is correct
3 Correct 10 ms 480 KB Output is correct
4 Correct 10 ms 672 KB Output is correct

Subtask #2
15.0 / 15.0

# 결과 실행 시간 메모리 Grader output
1 Correct 20 ms 688 KB Output is correct
2 Correct 26 ms 688 KB Output is correct
3 Correct 20 ms 688 KB Output is correct
4 Correct 28 ms 688 KB Output is correct

Subtask #3
14.0 / 18.0

# 결과 실행 시간 메모리 Grader output
1 Partially correct 116 ms 688 KB Output is partially correct
2 Partially correct 111 ms 808 KB Output is partially correct
3 Partially correct 164 ms 808 KB Output is partially correct
4 Partially correct 119 ms 808 KB Output is partially correct
5 Partially correct 109 ms 808 KB Output is partially correct
6 Partially correct 108 ms 808 KB Output is partially correct
7 Partially correct 107 ms 808 KB Output is partially correct
8 Partially correct 113 ms 808 KB Output is partially correct
9 Partially correct 138 ms 948 KB Output is partially correct
10 Partially correct 117 ms 948 KB Output is partially correct

Subtask #4
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 3 ms 948 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #5
0 / 53.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 7 ms 948 KB Output isn't correct
2 Halted 0 ms 0 KB -