제출 #592654

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
592654		andrei_boaca	Nuclearia (CEOI15_nuclearia)	C++14	30 / 100	1090 ms	436936 KiB

nuclearia

#include <bits/stdc++.h>
#pragma GCC optimize("O3")
using namespace std;
typedef long long ll;
typedef long double ld;
vector<vector<ll>> v;
int n,m,k,q;
int nradds=0;
void add(int x1,int y1,int x2,int y2,ll val)
{
    nradds++;
    x1=max(x1,1);
    y1=max(y1,1);
    x2=min(x2,n);
    y2=min(y2,m);
    v[x1][y1]+=val;
    v[x2+1][y1]-=val;
    v[x1][y2+1]-=val;
    v[x2+1][y2+1]+=val;
}
ll getsum(int x1,int y1,int x2,int y2)
{
    return v[x2][y2]-v[x1-1][y2]-v[x2][y1-1]+v[x1-1][y1-1];
}
int main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    cin>>n>>m>>k;
    v.resize(n+5);
    for(int i=0;i<=n+4;i++)
        v[i].resize(m+5);
    assert(k*max(n,m)<=1e8);
    for(int z=1;z<=k;z++)
    {
        int x,y,a,b;
        cin>>x>>y>>a>>b;
        int nr=a;
        int x1=x,y1=y,x2=x,y2=y;
        int cnt=0;
        while(nr>0&&cnt<=max(n,m))
        {
            add(x1,y1,x2,y2,b);
            nr-=b;
            cnt++;
            x1--;
            x2++;
            y1--;
            y2++;
            if(x1<=0&&y1<=0&&x2>n&&y2>m)
                break;
        }
        //cout<<v[1][1]<<' ';
        x1++;
        x2--;
        y1++;
        y2--;
        add(x1,y1,x2,y2,a);
        add(x1,y1,x2,y2,-cnt*b);
    }
    for(int i=1;i<=n;i++)
        for(int j=1;j<=m;j++)
            v[i][j]+=v[i-1][j]+v[i][j-1]-v[i-1][j-1];
    for(int i=1;i<=n;i++)
        for(int j=1;j<=m;j++)
        {
            v[i][j]=v[i][j]+v[i-1][j]+v[i][j-1]-v[i-1][j-1];
            //cout<<s[i][j]<<' ';
        }
    //assert(nradds<=k*max(n,m));
    cin>>q;
    while(q--)
    {
        int x1,y1,x2,y2;
        cin>>x1>>y1>>x2>>y2;
        ll suma=getsum(x1,y1,x2,y2);
        ll cells=(y2-y1+1)*(x2-x1+1);
        ll rez=round(ld(suma)/ld(cells));
        cout<<rez<<'\n';
    }
    return 0;
}

• Subtask 1: 3 / 3
• Subtask 2: 2 / 2
• Subtask 3: 3 / 3
• Subtask 4: 2 / 2
• Subtask 5: 6 / 6
• Subtask 6: 4 / 4
• Subtask 7: 6 / 6
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