이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "squares.h"
#include<bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
//#pragma GCC target("avx2")
//order_of_key #of elements less than x
// find_by_order kth element
#define ll long long
#define ld long double
#define pii pair<int,int>
#define f first
#define s second
#define pb push_back
#define REP(i,n) for(int i=0;i<n;i++)
#define REP1(i,n) for(ll i=1;i<=n;i++)
#define FILL(n,x) memset(n,x,sizeof(n))
#define ALL(_a) _a.begin(),_a.end()
#define sz(x) (int)x.size()
#define SORT_UNIQUE(c) (sort(c.begin(),c.end()),c.resize(distance(c.begin(),unique(c.begin(),c.end()))))
const ll maxn=2e3+5;
const ll maxlg=__lg(maxn)+2;
const ll INF64=4e18;
const int INF=0x3f3f3f3f;
const ll MOD=1e9+7;
const ld PI=acos(-1);
const ld eps=1e-6;
#define lowb(x) x&(-x)
#define MNTO(x,y) x=min(x,(__typeof__(x))y)
#define MXTO(x,y) x=max(x,(__typeof__(x))y)
template<typename T1,typename T2>
ostream& operator<<(ostream& out,pair<T1,T2> P){
out<<P.f<<' '<<P.s;
return out;
}
template<typename T>
ostream& operator<<(ostream& out,vector<T> V){
REP(i,sz(V)) out<<V[i]<<((i!=sz(V)-1)?" ":"\n");
return out;
}
ll mult(ll a,ll b){
return a*b%MOD;
}
ll mypow(ll a,ll b){
a%=MOD;
if(a==0) return 0;
if(b<=0) return 1;
ll res=1LL;
while(b){
if(b&1) res=(res*a)%MOD;
a=(a*a)%MOD;
b>>=1;
}
return res;
}
unordered_map<string,bool> vis;
string ans="";
int mp[maxn];
void dfs(string cur){
string tmp=cur+'0';
if(!vis.count(tmp)){
vis[tmp]=1;
dfs(tmp.substr(1));
ans.pb('0');
}
tmp=cur+'1';
if(!vis.count(tmp)){
vis[tmp]=1;
dfs(tmp.substr(1));
ans.pb('1');
}
}
void gen(){
if(sz(vis)) return;
ans.clear(),vis.clear();
string s="";
REP(i,9) s.pb('0');
dfs(s);
ans+=s;
REP(i,sz(ans)-9){
int x=0;
REP(j,10){
x=x*2+(ans[i+j]-'0');
}
mp[x]=i;
}
}
std::vector<int> paint(int n) {
vector<int> v(n+1,0);
v[n]=10;
gen();
REP(j,n) v[j]=ans[j]-'0';
return v;
}
int find_location(int n, std::vector<int> c) {
gen();
int x=0;
REP(j,10){
if(c[j]==-1){
return n-j;
}
x=x*2+c[j];
}
return mp[x];
}
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