oj.uz

답안 #59195

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
59195 2018-07-21T03:39:27 Z Benq The Forest of Fangorn (CEOI14_fangorn) C++14
50 / 100
 3000 ms 976 KB 
#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>

using namespace std;
using namespace __gnu_pbds;
 
typedef long long ll;
typedef long double ld;
typedef complex<double> cd;

typedef pair<int, int> pi;
typedef pair<ll,ll> pl;
typedef pair<double,double> pd;

typedef vector<int> vi;
typedef vector<double> vd;
typedef vector<ll> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;
typedef vector<cd> vcd;

template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>;

#define FOR(i, a, b) for (int i=a; i<(b); i++)
#define F0R(i, a) for (int i=0; i<(a); i++)
#define FORd(i,a,b) for (int i = (b)-1; i >= a; i--)
#define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--)

#define sz(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define all(x) x.begin(), x.end()

const int MOD = 1000000007;
const ll INF = 1e18;
const int MX = 100001;

double w,h,peri;
int c,n;
vpi C;
pi p[2000],g;
vector<pair<cd,cd>> a;

pi operator-(const pi& l, const pi& r) {
    return {l.f-r.f,l.s-r.s};
}

cd inter(pi x, pi y) {
    double mul = 1e18;
    if (y.f > 0) mul = min(mul,(double)(w-x.f)/y.f);
    if (y.f < 0) mul = min(mul,-(double)x.f/y.f);
    if (y.s > 0) mul = min(mul,(double)(h-x.s)/y.s);
    if (y.s < 0) mul = min(mul,-(double)x.s/y.s);
    // cout << "AH " << mul << "\n";
    return {x.f+mul*y.f,x.s+mul*y.s};
}

bool eq(double a, double b) {
    return abs(a-b) <= 1e-8;
}

double GET(cd x) {
    if (eq(x.imag(),0)) return x.real();
    if (eq(x.real(),w)) return w+x.imag();
    if (eq(x.imag(),h)) return w+h+w-x.real();
    return peri-x.imag();
}

int main() {
    ios_base::sync_with_stdio(0); cin.tie(0);
    cin >> w >> h >> g.f >> g.s;
    peri = 2*(w+h);
    cin >> c; C.resize(c); // assume connected region
    F0R(i,c) cin >> C[i].f >> C[i].s;
    cin >> n;
    F0R(i,n) cin >> p[i].f >> p[i].s;
    F0R(i,n) {
        vector<pair<pi,int>> v;
        F0R(j,n) if (j != i) v.pb({p[i]-p[j],0});
        v.pb({g-p[i],1});
        sort(all(v),[](pair<pi,int> x, pair<pi,int> y) { return atan2(x.f.s,x.f.f) < atan2(y.f.s,y.f.f); });
        int ind = 0; while (!v[ind].s) ind ++;
        a.pb({inter(p[i],v[(ind+sz(v)-1)%sz(v)].f),inter(p[i],v[(ind+1)%sz(v)].f)});
        // for (auto a: v) cout << a.f.f << " " << a.f.s << " " << a.s << "\n";
        // cout << "---\n";
    }
    vector<pair<double,int>> z;
    for (auto x: a) {
        double l = GET(x.f), r = GET(x.s);
        if (l > r) r += peri;
        z.pb({l-peri,1}); z.pb({r-peri,-1});
        z.pb({l,1}); z.pb({r,-1});
    }
    F0R(i,c) z.pb({GET(cd(C[i].f,C[i].s)),i+1+MOD});
    sort(all(z));
    int co = 0;
    vi res;
    for (auto x: z) {
        if (x.s == -1) co --;
        else if (x.s == 1) co ++;
        else {
            x.s -= MOD;
            if (co == sz(a)) res.pb(x.s);
        }
    }
    cout << sz(res) << "\n";
    sort(all(res));
    for (int i: res) cout << i << " ";
}

/* Look for:
* the exact constraints (multiple sets are too slow for n=10^6 :( ) 
* special cases (n=1?)
* overflow (ll vs int?)
* array bounds
*/

Subtask #1
30.0 / 30.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 380 KB Output is correct
2 Correct 3 ms 452 KB Output is correct
3 Correct 3 ms 452 KB Output is correct
4 Correct 3 ms 600 KB Output is correct
5 Correct 3 ms 600 KB Output is correct
6 Correct 3 ms 600 KB Output is correct
7 Correct 7 ms 600 KB Output is correct
8 Correct 6 ms 600 KB Output is correct

Subtask #2
20.0 / 20.0

# 결과 실행 시간 메모리 Grader output
1 Correct 4 ms 600 KB Output is correct
2 Correct 5 ms 600 KB Output is correct
3 Correct 9 ms 600 KB Output is correct
4 Correct 11 ms 600 KB Output is correct
5 Correct 9 ms 600 KB Output is correct
6 Correct 20 ms 600 KB Output is correct
7 Correct 3 ms 620 KB Output is correct
8 Correct 3 ms 620 KB Output is correct
9 Correct 5 ms 620 KB Output is correct
10 Correct 36 ms 620 KB Output is correct
11 Correct 33 ms 620 KB Output is correct
12 Correct 54 ms 620 KB Output is correct

Subtask #3
0 / 30.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 624 KB Output is correct
2 Correct 4 ms 624 KB Output is correct
3 Correct 4 ms 624 KB Output is correct
4 Incorrect 1341 ms 940 KB Output isn't correct
5 Halted 0 ms 0 KB -

Subtask #4
0 / 20.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 3031 ms 976 KB Time limit exceeded
2 Halted 0 ms 0 KB -