제출 #591789

#제출 시각아이디문제언어결과실행 시간메모리
591789jeroenodb휴가 (IOI14_holiday)C++14
47 / 100
113 ms6140 KiB
#include"holiday.h" // #include "grader.cpp" #include "bits/stdc++.h" using namespace std; #define all(x) begin(x),end(x) template<typename A, typename B> ostream& operator<<(ostream &os, const pair<A, B> &p) { return os << '(' << p.first << ", " << p.second << ')'; } template<typename T_container, typename T = typename enable_if<!is_same<T_container, string>::value, typename T_container::value_type>::type> ostream& operator<<(ostream &os, const T_container &v) { string sep; for (const T &x : v) os << sep << x, sep = " "; return os; } #define debug(a) cerr << "(" << #a << ": " << a << ")\n"; typedef long long ll; typedef vector<int> vi; typedef vector<vi> vvi; typedef pair<int,int> pi; const int mxN = 1e5+1, oo = 1e9; struct node { int active=0; ll sm=0; void merge(const node& o) { active+=o.active; sm+=o.sm; } friend node merge(node a, const node& b) { a.merge(b); return a; } }; vi cs; struct segtree { int ptwo; vector<node> seg; segtree(){} node& operator[](int i) { return seg[i+ptwo]; } segtree(int nn) { ptwo=1; while(ptwo<nn) ptwo*=2; seg.resize(ptwo*2); } ll good(int d) { if(d<0) return -oo; int at=1; ll ans=0; while(at<ptwo) { at*=2; if(seg[at+1].active<d) { ans+=seg[at+1].sm; d-=seg[at+1].active; } else at++; } return ans+min(seg[at].sm,cs[at-ptwo]*ll(d)); } void update(int i, int val, int sgn) { assert(i>=0 and i<ptwo); i+=ptwo; seg[i].sm+=sgn*val; seg[i].active+=sgn; for(i/=2;i>=1;i/=2) { seg[i] = merge(seg[2*i],seg[2*i+1]); } } void build() { for(int i=ptwo-1;i>=1;--i) { seg[i] = merge(seg[2*i],seg[2*i+1]); } } }; segtree seg; ll ans=0; void solve(int l, int r, int a, int b, int d, int atr[]) { if(a>b or l>r) return; int mid = (l+r)/2; pair<ll,int> opt; if(d>=r-mid+1) { d++; for(int i=mid;i<=r;++i) { d--; seg.update(atr[i],cs[atr[i]],1); } opt = {seg.good(d),a}; for(int i=a+1;i<=b;++i) { seg.update(atr[i],cs[atr[i]],1); d-=2; opt = max(opt,{seg.good(d),i}); } ans = max(ans,opt.first); for(int i=a+1;i<=b;++i) { seg.update(atr[i],cs[atr[i]],-1); d+=2; } solve(l,mid-1,a,opt.second,d-1,atr); for(int i=mid;i<=r;++i) { d++; seg.update(atr[i],cs[atr[i]],-1); } d--; } for(int i=a+1;i<=opt.second;++i) { seg.update(atr[i],cs[atr[i]],1); d-=2; } solve(mid+1,r,opt.second,b,d,atr); for(int i=a+1;i<=opt.second;++i) { seg.update(atr[i],cs[atr[i]],-1); } } long long int findMaxAttraction(int n, int start, int d, int attraction[]) { ans=0; cs = vi(attraction,attraction+n); sort(all(cs)); cs.erase(unique(all(cs)),cs.end()); for(int i=0;i<n;++i) { attraction[i] = lower_bound(all(cs),attraction[i])-cs.begin(); } seg = segtree(cs.size()); for(int rep=0;rep<2;++rep) { solve(0,start,start,n-1,d,attraction); reverse(attraction,attraction+n); start=n-1-start; } return ans; }
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