Submission #591726

#TimeUsernameProblemLanguageResultExecution timeMemory
591726piOOEPotatoes and fertilizers (LMIO19_bulves)C++17
100 / 100
138 ms15232 KiB
#include <bits/stdc++.h> using namespace std; #include <ext/pb_ds/assoc_container.hpp> using namespace __gnu_pbds; template<typename T> using ordered_set = tree<T, null_type, less < T>, rb_tree_tag, tree_order_statistics_node_update>; template<typename T> using normal_queue = priority_queue<T, vector<T>, greater<T>>; mt19937 rnd(chrono::steady_clock::now().time_since_epoch().count()); #define ll long long #define trace(x) cout << #x << ": " << (x) << endl; #define all(x) begin(x), end(x) #define rall(x) rbegin(x), rend(x) #define uniq(x) x.resize(unique(all(x)) - begin(x)) #define ld long double #define sz(s) (int) size(s) #define pii pair<int, int> #define mp(x, y) make_pair(x, y) #define mt make_tuple #define int128 __int128 template<typename T> bool ckmin(T &x, T y) { if (x > y) { x = y; return true; } return false; } template<typename T> bool ckmax(T &x, T y) { if (x < y) { x = y; return true; } return false; } int bit(int x, int b) { return (x >> b) & 1; } int rand(int l, int r) { return (int) ((ll) rnd() % (r - l + 1)) + l; } const ll infL = 3e18; const int infI = 1e9 + 7; const int N = 500001; const ll mod = 1e9 + 7; const ld eps = 1e-9; ll A[N]; int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int n; cin >> n; for (int i = 0; i < n; ++i) { int a, b; cin >> a >> b; A[i] = (i ? A[i - 1] : 0) + a - b; } ll ans = 0; for (int i = 0; i < n; ++i) { if (A[i] < 0) { //it means that on our prefix sum(b) > sum(a) so we have to take some a's from right and put them here ans += -A[i]; A[i] = 0; } if (A[i] > A[n - 1]) { //it means that now we have to take some from here and put them righter ans += A[i] - A[n - 1]; A[i] = A[n - 1]; } } //now everything on every prefix is alright so let's go to solve classic problem about making this array non-decreasing priority_queue<ll> pq; for (int i = 0; i < n; ++i) { pq.push(A[i]); pq.push(A[i]); ans += pq.top() - A[i]; pq.pop(); } cout << ans; return 0; }
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