Submission #589019

#TimeUsernameProblemLanguageResultExecution timeMemory
589019maomao90Boarding Passes (BOI22_passes)C++17
Compilation error
0 ms0 KiB
// Hallelujah, praise the one who set me free // Hallelujah, death has lost its grip on me // You have broken every chain, There's salvation in your name // Jesus Christ, my living hope #include <bits/stdc++.h> using namespace std; #define REP(i, s, e) for (int i = (s); i < (e); i++) #define RREP(i, s, e) for (int i = (s); i >= (e); i--) template <class T> inline bool mnto(T& a, T b) {return a > b ? a = b, 1 : 0;} template <class T> inline bool mxto(T& a, T b) {return a < b ? a = b, 1: 0;} typedef long long ll; typedef long double ld; #define FI first #define SE second typedef pair<int, int> ii; typedef pair<ll, ll> pll; typedef tuple<int, int, int> iii; #define ALL(_a) _a.begin(), _a.end() #define SZ(_a) (int) _a.size() #define pb push_back typedef vector<int> vi; typedef vector<ll> vll; typedef vector<ii> vii; typedef vector<iii> viii; #ifndef DEBUG #define cerr if (0) cerr #endif const int INF = 1000000005; const ll LINF = 1000000000000000005ll; const int MAXN = 100005; int n, g; string s; ld calc(ld n) { return (ld) (n * (n - 1) / 2) / 2; } int main() { #ifndef DEBUG ios::sync_with_stdio(0), cin.tie(0); #endif cout << setprecision(9); cin >> s; n = SZ(s); REP (i, 0, n) { mxto(g, s[i] - 'A' + 1); } assert(g == 1); int ln = n / 2, rn = n - ln; ld ans = (ll) ln * (ln - 1) / 2 + (ll) rn * (rn - 1) / 2; if (ans % 2 == 0) { ans /= 2; cout << ans << '\n'; } else { ans /= 2; cout << ans << ".5\n"; } return 0; }

Compilation message (stderr)

passes.cpp: In function 'int main()':
passes.cpp:58:13: error: invalid operands of types 'ld' {aka 'long double'} and 'int' to binary 'operator%'
   58 |     if (ans % 2 == 0) {
      |         ~~~ ^ ~
      |         |     |
      |         |     int
      |         ld {aka long double}