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답안 #588710

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
588710 2022-07-03T22:26:59 Z Bungmint Palindrome-Free Numbers (BOI13_numbers) C++17
96.25 / 100
 1 ms 340 KB 
// Copyright © 2022 Youngmin Park. All rights reserved.
//#pragma GCC optimize("O3")
//#pragma GCC target("avx2")
#include <bits/stdc++.h>
using namespace std;

using ll = long long;
using vi = vector<int>;
using pii = pair<int, int>;
using vpi = vector<pii>;
using pll = pair<ll, ll>;
using vl = vector<ll>;
using vpl = vector<pll>;
using ld = long double;
template <typename T, size_t SZ>
using ar = array<T, SZ>;
template <typename T>
using pqg = priority_queue<T, vector<T>, greater<T>>;

#define all(v) (v).begin(), (v).end()
#define pb push_back
#define sz(x) (int)(x).size()
#define fi first
#define se second
#define lb lower_bound
#define ub upper_bound

constexpr int INF = 1e9;
constexpr ll LINF = 1e18;
const ld PI = acos((ld)-1.0);
constexpr int dx[4] = {1, 0, -1, 0}, dy[4] = {0, 1, 0, -1};
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
template <typename T>
constexpr bool ckmin(T &a, const T &b) { return b < a ? a = b, 1 : 0; }
template <typename T>
constexpr bool ckmax(T &a, const T &b) { return b > a ? a = b, 1 : 0; }

template <typename A, typename B>
ostream &operator<<(ostream &os, const pair<A, B> &p)
{
	return os << '(' << p.first << ", " << p.second << ')';
}
template <typename T_container, typename T = typename enable_if<!is_same<T_container, string>::value, typename T_container::value_type>::type>
ostream &operator<<(ostream &os, const T_container &v)
{
	os << '{';
	string sep;
	for (const T &x : v)
		os << sep << x, sep = ", ";
	return os << '}';
}
template <typename T>
ostream &operator<<(ostream &os, const deque<T> &v) {
	os << vector<T>(all(v));
	return os;
}
template <typename T, typename S, typename C>
ostream &operator<<(ostream &os, priority_queue<T, S, C> pq) {
	vector<T> v;
	while (sz(pq)) {
		v.pb(pq.top());
		pq.pop();
	}
	os << v;
	return os;
}
void dbg_out()
{
	cerr << "\033[0m" << endl;
}
template <typename Head, typename... Tail>
void dbg_out(Head H, Tail... T)
{
	cerr << ' ' << H;
	dbg_out(T...);
}
#ifdef LOCAL
#define dbg(...) cerr << "\033[1;35m" << __func__ << ':' << __LINE__ << " (" << #__VA_ARGS__ << "):\033[33m", dbg_out(__VA_ARGS__)
#else
#define dbg(...) 42
#endif

inline namespace RecursiveLambda
{
	template <typename Fun>
	struct y_combinator_result
	{
		Fun fun_;
		template <typename T>
		explicit y_combinator_result(T &&fun) : fun_(forward<T>(fun)) {}
		template <typename... Args>
		decltype(auto) operator()(Args &&...args)
		{
			return fun_(ref(*this), forward<Args>(args)...);
		}
	};
	template <typename Fun>
	decltype(auto) y_combinator(Fun &&fun)
	{
		return y_combinator_result<decay_t<Fun>>(forward<Fun>(fun));
	}
};

inline namespace Range {
	class ForwardRange {
		int src, dst;

	  public:
	  	explicit constexpr ForwardRange(const int l, const int r) : src(l), dst(r) {}
		explicit constexpr ForwardRange(const int n) : src(0), dst(n) {}
		constexpr ForwardRange begin() const { return *this; }
		constexpr monostate end() const { return {}; }
		constexpr bool operator!=(monostate) const { return src < dst; }
		constexpr void operator++() const {}
		constexpr int operator*() { return src++; }
	};
	class BackwardRange {
		int src, dst;

	  public:
	  	explicit constexpr BackwardRange(const int l, const int r) : src(r), dst(l) {}
		explicit constexpr BackwardRange(const int n) : src(n), dst(0) {}
		constexpr BackwardRange begin() const { return *this; }
		constexpr monostate end() const { return {}; }
		constexpr bool operator!=(monostate) const { return src > dst; }
		constexpr void operator++() const {}
		constexpr int operator*() { return --src; }
	};
	using rep = ForwardRange;
	using per = BackwardRange;
};

ll dp[22][121][2][2];
vi num;

void init(ll x) {
	num.clear();
	while (x) num.pb(x % 10), x /= 10;
	reverse(all(num));
	memset(dp, -1, sizeof(dp));
}
ll dfs(int pos, int pr, bool fl, bool nonzr) {
	if (pos == sz(num)) {
		return nonzr;
	}
	ll& state = dp[pos][pr][fl][nonzr];
	if (state != -1) return state;
	state = 0;
	int LMT = (fl ? 9 : num[pos]);
	for (int i : rep(LMT + 1)) {
		int a = pr / 11, b = pr % 11;
		int nxt = b * 11 + i;
		if (nonzr) {
			if ((i == a || i == b) && i) continue;
			if (i == 0 && (a != 10 && b != 10)) {
				nxt += 10;
				state += dfs(pos + 1, nxt, fl || i < LMT, nonzr || i);
			}else if (i) state += dfs(pos + 1, nxt, fl || i < LMT, nonzr || i);
		}else{
			state += dfs(pos + 1, nxt, fl || i < LMT, nonzr || i);
		}
	}
	return state;
}

void solve()
{
	ll l, r;
	cin >> l >> r;
	ll lans{}, rans{};
	init(r);
	rans = dfs(0, 0, 0, 0);
	dbg(rans);
	init(l - 1);
	lans = dfs(0, 0, 0, 0);
	cout << rans - lans << '\n';
}

int main()
{
	cin.tie(0)->sync_with_stdio(0);
	cin.exceptions(cin.failbit);
	int testcase = 1;
	// cin >> testcase;
	while (testcase--)
	{
		solve();
	}
#ifdef LOCAL
	cerr << "Time elapsed: " << 1.0 * (double)clock() / CLOCKS_PER_SEC << " s.\n";
#endif
}

Compilation message

numbers.cpp: In function 'void solve()':
numbers.cpp:80:18: warning: statement has no effect [-Wunused-value]
   80 | #define dbg(...) 42
      |                  ^~
numbers.cpp:173:2: note: in expansion of macro 'dbg'
  173 |  dbg(rans);
      |  ^~~

Subtask #1
21.25 / 25.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 340 KB Output is correct
2 Correct 0 ms 340 KB Output is correct
3 Correct 1 ms 340 KB Output is correct
4 Incorrect 0 ms 340 KB Output isn't correct
5 Correct 1 ms 340 KB Output is correct
6 Correct 1 ms 340 KB Output is correct
7 Correct 0 ms 340 KB Output is correct
8 Correct 0 ms 340 KB Output is correct
9 Correct 0 ms 340 KB Output is correct
10 Correct 1 ms 340 KB Output is correct
11 Correct 1 ms 340 KB Output is correct
12 Correct 1 ms 324 KB Output is correct
13 Correct 1 ms 324 KB Output is correct
14 Incorrect 1 ms 340 KB Output isn't correct
15 Correct 1 ms 328 KB Output is correct
16 Correct 1 ms 340 KB Output is correct
17 Correct 1 ms 340 KB Output is correct
18 Incorrect 1 ms 340 KB Output isn't correct
19 Correct 1 ms 340 KB Output is correct
20 Correct 1 ms 340 KB Output is correct

Subtask #2
75.0 / 75.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 324 KB Output is correct
2 Correct 1 ms 340 KB Output is correct
3 Correct 1 ms 340 KB Output is correct
4 Correct 1 ms 340 KB Output is correct
5 Correct 1 ms 340 KB Output is correct
6 Correct 1 ms 340 KB Output is correct
7 Correct 1 ms 340 KB Output is correct
8 Correct 0 ms 320 KB Output is correct
9 Correct 0 ms 340 KB Output is correct
10 Correct 1 ms 340 KB Output is correct
11 Correct 1 ms 340 KB Output is correct
12 Correct 1 ms 340 KB Output is correct
13 Correct 1 ms 332 KB Output is correct
14 Correct 1 ms 340 KB Output is correct
15 Correct 1 ms 324 KB Output is correct
16 Correct 1 ms 340 KB Output is correct
17 Correct 1 ms 340 KB Output is correct
18 Correct 1 ms 340 KB Output is correct
19 Correct 1 ms 324 KB Output is correct
20 Correct 1 ms 340 KB Output is correct
21 Correct 1 ms 340 KB Output is correct
22 Correct 1 ms 332 KB Output is correct
23 Correct 1 ms 340 KB Output is correct
24 Correct 1 ms 340 KB Output is correct
25 Correct 1 ms 340 KB Output is correct
26 Correct 1 ms 340 KB Output is correct
27 Correct 1 ms 340 KB Output is correct
28 Correct 1 ms 332 KB Output is correct
29 Correct 1 ms 292 KB Output is correct
30 Correct 1 ms 340 KB Output is correct
31 Correct 1 ms 324 KB Output is correct
32 Correct 1 ms 340 KB Output is correct
33 Correct 1 ms 340 KB Output is correct
34 Correct 1 ms 340 KB Output is correct
35 Correct 1 ms 340 KB Output is correct
36 Correct 1 ms 340 KB Output is correct
37 Correct 1 ms 340 KB Output is correct
38 Correct 1 ms 340 KB Output is correct
39 Correct 1 ms 336 KB Output is correct
40 Correct 1 ms 328 KB Output is correct
41 Correct 1 ms 340 KB Output is correct
42 Correct 1 ms 340 KB Output is correct
43 Correct 1 ms 340 KB Output is correct
44 Correct 1 ms 340 KB Output is correct
45 Correct 1 ms 340 KB Output is correct