제출 #58869

#제출 시각아이디문제언어결과실행 시간메모리
58869BenqBomb (IZhO17_bomb)C++14
41 / 100
1095 ms132096 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/tree_policy.hpp> #include <ext/pb_ds/assoc_container.hpp> using namespace std; using namespace __gnu_pbds; typedef long long ll; typedef long double ld; typedef complex<ld> cd; typedef pair<int, int> pi; typedef pair<ll,ll> pl; typedef pair<ld,ld> pd; typedef vector<int> vi; typedef vector<ld> vd; typedef vector<ll> vl; typedef vector<pi> vpi; typedef vector<pl> vpl; typedef vector<cd> vcd; template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>; #define FOR(i, a, b) for (int i=a; i<(b); i++) #define F0R(i, a) for (int i=0; i<(a); i++) #define FORd(i,a,b) for (int i = (b)-1; i >= a; i--) #define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--) #define sz(x) (int)(x).size() #define mp make_pair #define pb push_back #define f first #define s second #define lb lower_bound #define ub upper_bound #define all(x) x.begin(), x.end() const int MOD = 1000000007; const ll INF = 1e18; const int MX = 2505; int cum1[MX][MX], cum2[MX][MX]; char gr[MX][MX]; int n,m; bool ok(int x, int y) { FOR(i,1,n+1) FOR(j,1,m+1) cum2[i][j] = 0; F0R(i,n+1-x) F0R(j,m+1-y) if (cum1[i+x][j+y]-cum1[i][j+y]-cum1[i+x][j]+cum1[i][j] == x*y) { cum2[i+1][j+1] ++; cum2[i+1][j+1+y] --; cum2[i+1+x][j+1] --; cum2[i+1+x][j+1+y] ++; } FOR(i,1,n+1) FOR(j,1,m+1) { cum2[i][j] += cum2[i][j-1]+cum2[i-1][j]-cum2[i-1][j-1]; if (gr[i][j] == '1' && !cum2[i][j]) return 0; } return 1; } int main() { // freopen("bomb.in","r",stdin); // freopen("bomb.out","w",stdout); cin >> n >> m; FOR(i,1,n+1) FOR(j,1,m+1) { cin >> gr[i][j]; cum1[i][j] = cum1[i-1][j]+cum1[i][j-1]-cum1[i-1][j-1]; if (gr[i][j] == '1') cum1[i][j] ++; } int x = 0, ans = 0; FORd(i,1,n+1) { while (ok(i,x+1)) x ++; ans = max(ans,i*x); } cout << ans; } /* Look for: * the exact constraints (multiple sets are too slow for n=10^6 :( ) * special cases (n=1?) * overflow (ll vs int?) * array bounds */
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