Submission #585941

#	Time	Username	Problem	Language	Result	Execution time	Memory
585941		MilosMilutinovic	Lozinke (COCI17_lozinke)	C++14	100 / 100	270 ms	13504 KiB

lozinke

#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <algorithm>
#include <cmath>
#include <vector>
#include <set>
#include <map>
#include <unordered_set>
#include <unordered_map>
#include <queue>
#include <ctime>
#include <cassert>
#include <complex>
#include <string>
#include <cstring>
#include <chrono>
#include <random>
#include <bitset>
#include <array>
using namespace std;
 
#ifdef LOCAL
	#define eprintf(...) {fprintf(stderr, __VA_ARGS__);fflush(stderr);}
#else
	#define eprintf(...) 42
#endif
 
using ll = long long;
using ld = long double;
using uint = unsigned int;
using ull = unsigned long long;
template<typename T>
using pair2 = pair<T, T>;
using pii = pair<int, int>;
using pli = pair<ll, int>;
using pll = pair<ll, ll>;
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
ll myRand(ll B) {
	return (ull)rng() % B;
}
 
#define pb push_back
#define mp make_pair
#define all(x) (x).begin(),(x).end()
#define fi first
#define se second
 
clock_t startTime;
double getCurrentTime() {
	return (double)(clock() - startTime) / CLOCKS_PER_SEC;
}

const int B1 = 453571;
const int MOD1 = 1e9 + 9;
const int B2 = 744313;
const int MOD2 = 1e9 + 7;

const int N = 20020;
string s[N];
int n;

int main() 
{
	ios::sync_with_stdio(false);
	cin.tie(nullptr);

	startTime = clock();
//	freopen("input.txt", "r", stdin);
//	freopen("output.txt", "w", stdout);
	
	cin >> n;
	for (int i = 0; i < n; i++)
		cin >> s[i];
	sort(s, s + n, [&](string a, string b) {
		if (a.size() != b.size())
			return a.size() < b.size();
		return a < b;
	});
	map<pii, int> cnt;
	ll ans = 0;
	for (int i = 0; i < n; i++) {
		int m = (int)s[i].size();
		ll myHash1 = 0;
		ll myHash2 = 0;
		set<pair<ll, ll>> st;
		for (int l = 0; l < m; l++) {
			ll hsh1 = 0, hsh2 = 0;
			for (int r = l; r < m; r++) {
				hsh1 = hsh1 * B1 + (s[i][r] - 'a' + 1);
				hsh1 %= MOD1; 
				hsh2 = hsh2 * B2 + (s[i][r] - 'a' + 1);
				hsh2 %= MOD2; 
				st.insert(mp(hsh1, hsh2));
			}
			if (l == 0) 
				myHash1 = hsh1, myHash2 = hsh2;
		}
		for (auto p : st)
			ans += cnt[p];
		cnt[mp(myHash1, myHash2)]++;		
	}
	for (auto& p : cnt) {
		ans += (ll)p.second * (p.second - 1) / 2;
	}
	printf("%lld", ans);

	return 0;
}

• Subtask 1: 100 / 100