제출 #585937

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
585937		MilosMilutinovic	Lozinke (COCI17_lozinke)	C++14	90 / 100	234 ms	10316 KiB

lozinke

#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <algorithm>
#include <cmath>
#include <vector>
#include <set>
#include <map>
#include <unordered_set>
#include <unordered_map>
#include <queue>
#include <ctime>
#include <cassert>
#include <complex>
#include <string>
#include <cstring>
#include <chrono>
#include <random>
#include <bitset>
#include <array>
using namespace std;
 
#ifdef LOCAL
	#define eprintf(...) {fprintf(stderr, __VA_ARGS__);fflush(stderr);}
#else
	#define eprintf(...) 42
#endif
 
using ll = long long;
using ld = long double;
using uint = unsigned int;
using ull = unsigned long long;
template<typename T>
using pair2 = pair<T, T>;
using pii = pair<int, int>;
using pli = pair<ll, int>;
using pll = pair<ll, ll>;
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
ll myRand(ll B) {
	return (ull)rng() % B;
}
 
#define pb push_back
#define mp make_pair
#define all(x) (x).begin(),(x).end()
#define fi first
#define se second
 
clock_t startTime;
double getCurrentTime() {
	return (double)(clock() - startTime) / CLOCKS_PER_SEC;
}

const int B = 453571;
const int MOD = 1e9 + 7;

const int N = 20020;
string s[N];
int n;

int main() 
{
	ios::sync_with_stdio(false);
	cin.tie(nullptr);

	startTime = clock();
//	freopen("input.txt", "r", stdin);
//	freopen("output.txt", "w", stdout);
	
	cin >> n;
	for (int i = 0; i < n; i++)
		cin >> s[i];
	sort(s, s + n, [&](string a, string b) {
		if (a.size() != b.size())
			return a.size() < b.size();
		return a < b;
	});
	map<int, int> cnt;
	ll ans = 0;
	for (int i = 0; i < n; i++) {
		int m = (int)s[i].size();
		ll myHash = 0;
		set<ll> st;
		for (int l = 0; l < m; l++) {
			ll hsh = 0;
			for (int r = l; r < m; r++) {
				hsh = hsh * B + (s[i][r] - 'a' + 1);
				hsh %= MOD; 
				st.insert(hsh);
			}
			if (l == 0) 
				myHash = hsh;
		}
		for (auto p : st)
			ans += cnt[p];
		cnt[myHash]++;		
	}
	for (auto& p : cnt) {
		ans += (ll)p.second * (p.second - 1) / 2;
	}
	printf("%lld", ans);

	return 0;
}

• Subtask 1: 90 / 100