이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair <int, int> pii;
typedef pair <ll, ll> pll;
#define pb push_back
#define mp make_pair
#define all(v) (v).begin(),(v).end()
#define rall(v) (v).rbegin(),(v).rend()
#define lb lower_bound
#define ub upper_bound
#define sz(v) int((v).size())
#define do_not_disturb ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define endl '\n'
const int N = 1e5 + 7;
ll ans, pigeons[N], subtree[N];
int n, bread;
vector <int> graph[N];
void dfs(int v, int p) {
subtree[v] = 0;
for (auto to : graph[v]) {
if (to == p) continue;
subtree[v] += pigeons[to];
dfs(to, v);
}
}
void count(int v, int p, ll collected, int level = 1) {
if (level == bread) {
ans = max(ans, collected);
return;
}
for (auto to : graph[v]) {
if (to == p) continue;
count(to, v, collected + subtree[to], level + 1);
}
}
void solve() {
cin >> n >> bread;
for (int i = 1; i <= n; i++) {
cin >> pigeons[i];
}
for (int i = 0; i < n - 1; i++) {
int a, b;
cin >> a >> b;
graph[a].pb(b);
graph[b].pb(a);
}
for (int i = 1; i <= n; i++) {
dfs(i, i);
count(i, i, subtree[i]);
}
cout << ans;
}
int main() {
do_not_disturb
int t = 1;
//~ cin >> t;
while (t--) {
solve();
}
return 0;
}
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