제출 #585484

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
585484		Shin	최솟값 배열 (IZhO11_hyper)	C++14	100 / 100	462 ms	37324 KiB

hyper

#include <bits/stdc++.h>
#define fi first
#define se second
#define mp make_pair
#define all(x) x.begin(), x.end()

using namespace std;
template <class X, class Y> bool minimize(X &a, Y b) {
    if (a > b) return a = b, true;
    return false;
}
template <class X, class Y> bool maximize(X &a, Y b) {
    if (a < b) return a = b, true;
    return false;
}
 
signed main() {
  cin.tie(0)->sync_with_stdio(0);
  int n, m; cin >> n >> m;
  vector<vector<vector<vector<int>>>> a(n + 1, vector<vector<vector<int>>>(n + 1, vector<vector<int>>(n + 1, vector<int>(n + 1))));
  for (int i = 1; i <= n; i ++) {
    for (int j = 1; j <= n; j ++) {
      for (int ii = 1; ii <= n; ii ++) {
        for (int jj = 1; jj <= n; jj ++) {
          cin >> a[i][j][ii][jj];
        }
      }
    }
  }
  for (int i = 1; i <= n; i ++) {
    for (int j = 1; j <= n; j ++) {
      for (int ii = 1; ii <= n; ii ++) {
        for (int jj = 1; jj <= n; jj ++) {
          for (int k = 1; k < m; k ++) {
            if (jj + k > n) break;
            minimize(a[i][j][ii][jj], a[i][j][ii][jj + k]);
          }
        }
      }
      for (int ii = 1; ii <= n; ii ++) {
        for (int jj = 1; jj <= n; jj ++) {
          for (int k = 1; k < m; k ++) {
            if (ii + k > n) break;
            minimize(a[i][j][ii][jj], a[i][j][ii + k][jj]);
          }
        }
      }
    }
    for (int j = 1; j <= n; j ++) {
      for (int ii = 1; ii <= n; ii ++) {
        for (int jj = 1; jj <= n; jj ++) {
          for (int k = 1; k < m; k ++) {
            if (j + k > n) break;
            minimize(a[i][j][ii][jj], a[i][j + k][ii][jj]);
          }
        }
      }
    }
  }
  for (int i = 1; i <= n; i ++) {
    for (int j = 1; j <= n; j ++) {
      for (int ii = 1; ii <= n; ii ++) {
        for (int jj = 1; jj <= n; jj ++) {
          for (int k = 1; k < m; k ++) {
            if (k + i > n) break;
            minimize(a[i][j][ii][jj], a[i + k][j][ii][jj]);
          }
        }
      }
    }
  }
  for (int i = 1; i + m - 1 <= n; i ++) {
    for (int j = 1; j + m - 1 <= n; j ++) {
      for (int ii = 1; ii + m - 1 <= n; ii ++) {
        for (int jj = 1; jj + m - 1 <= n; jj ++) {
          cout << a[i][j][ii][jj] << " ";
        }
      }
    }
  }
  return 0;
}

• Subtask 1: 100 / 100