#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N = (int) 1e5 + 7;
const int B = 100 + 7;
const ll INF = (ll) 1e18 + 7;
int n, bread_have, pigs[N];
vector<int> g[N];
ll sum_vecs[N];
ll dp1[N][B];
ll dp2[N][B];
ll dp3[N][B];
ll sol;
void dfs1(int a, int p = 0) {
for (auto &b : g[a]) {
if (b != p) {
dfs1(b, a);
}
}
for (int i = 0; i <= bread_have; i++) {
if (i >= 1) {
dp1[a][i] = max(dp1[a][i], sum_vecs[a]);
}
}
for (auto &b : g[a]) {
if (b == p) {
continue;
}
for (int i = 0; i <= bread_have; i++) {
dp1[a][i] = max(dp1[a][i], dp1[b][i]);
if (i >= 1) {
dp1[a][i] = max(dp1[a][i], dp1[b][i - 1] + (sum_vecs[a] - pigs[b]));
}
}
}
}
void dfs2(int a, int p = 0) {
for (auto &b : g[a]) {
if (b != p) {
dfs2(b, a);
}
}
for (auto &b : g[a]) {
if (b == p) {
continue;
}
for (int i = 0; i <= bread_have; i++) {
dp2[a][i] = max(dp2[a][i], dp2[b][i]);
if (i >= 1) {
dp2[a][i] = max(dp2[a][i], dp2[b][i - 1] + (sum_vecs[a] - pigs[p]));
}
}
}
for (auto &b : g[a]) {
if (b == p) {
continue;
}
for (int i = 0; i <= bread_have; i++) {
dp3[a][i] = max(dp3[a][i], dp2[b][i]);
if (i >= 1) {
dp3[a][i] = max(dp3[a][i], dp2[b][i - 1] + sum_vecs[a]);
}
}
}
}
void dfs3(int a, int p = 0) {
vector<int> Kids;
for (auto &b : g[a]) {
if (b != p) {
dfs3(b, a);
Kids.push_back(b);
}
}
g[a] = Kids;
sol = max(sol, sum_vecs[a]);
sol = max(sol, dp1[a][bread_have]);
sol = max(sol, dp2[a][bread_have]);
sol = max(sol, dp3[a][bread_have]);
for (auto &b : Kids) {
for (auto &c : Kids) {
if (b == c) {
continue;
}
for (int i = 0; i <= bread_have; i++) {
sol = max(sol, dp1[b][i] + dp2[c][bread_have - i]);
}
for (int i = 0; i + 1 <= bread_have; i++) {
sol = max(sol, dp1[b][i] + dp2[c][bread_have - i - 1] + (sum_vecs[a] - pigs[b]));
}
}
}
}
signed main() {
ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
cin >> n >> bread_have;
for (int i = 1; i <= n; i++) {
cin >> pigs[i];
}
for (int i = 1; i < n; i++) {
int a, b;
cin >> a >> b;
g[a].push_back(b);
g[b].push_back(a);
sum_vecs[a] += pigs[b];
sum_vecs[b] += pigs[a];
}
if (bread_have == 0) {
cout << "0\n";
return 0;
}
dfs1(1);
dfs2(1);
dfs3(1);
cout << sol << "\n";
}
