Submission #583016

#TimeUsernameProblemLanguageResultExecution timeMemory
583016elkernosTreatment Project (JOI20_treatment)C++17
0 / 100
105 ms11532 KiB
#include <bits/stdc++.h> using namespace std; const int oo = 1e9; struct Tree { typedef pair<int, int> T; static constexpr T unit = {-oo, -oo}; T f(T a, T b) { return max(a, b); } vector<T> s; int n; Tree(int nn) : s(2 * nn, unit), n(nn) {} void update(int pos, T val) { for(s[pos += n] = val; pos /= 2;) { s[pos] = f(s[pos * 2], s[pos * 2 + 1]); } } T query(int b, int e) { T ra = unit, rb = unit; for(b += n, e += n + 1; b < e; b /= 2, e /= 2) { if(b % 2) ra = f(ra, s[b++]); if(e % 2) rb = f(s[--e], rb); } return f(ra, rb); } }; struct treatment { int t, l, r, c; pair<int, int> pocz, kon; void read() { cin >> t >> l >> r >> c; r++; pocz.first = l + t; pocz.second = t - l; kon.first = r + t; kon.second = t - r; } bool operator<(const treatment &he) const { return pocz.first < he.pocz.first; } }; int main() { cin.tie(nullptr)->sync_with_stdio(0); int n, m; cin >> n >> m; vector<treatment> they(m + 1); for(int i = 1; i <= m; i++) { they[i].read(); } sort(they.begin() + 1, they.end()); Tree tree(m + 1); #define T pair<long long, int> priority_queue<T, vector<T>, greater<T>> q; const long long ool = 1e18 + 5; vector<long long> d(m + 1); for(int i = 1; i <= m; i++) { if(they[i].l == 1) { d[i] = they[i].c; q.push({d[i], i}); } else { d[i] = ool; tree.update(i, {they[i].pocz.second, i}); } } while(!q.empty()) { pair<long long, int> t = q.top(); q.pop(); while(true) { int lo = 1, hi = m, ans = 0; while(lo <= hi) { int mid = (lo + hi) / 2; if(they[t.second].kon.first < they[mid].pocz.first) { hi = mid - 1; } else { lo = mid + 1; ans = mid; } } pair<int, int> maybe = tree.query(1, ans); if(maybe.first < they[t.second].kon.second) { break; } assert(d[maybe.second] > they[maybe.second].c + t.first); q.emplace(d[maybe.second] = they[maybe.second].c + t.first, maybe.second); tree.update(maybe.second, {-oo, -oo}); } } long long ans = ool; for(int i = 1; i <= m; i++) { if(they[i].r == n + 1) { ans = min(ans, d[i]); } } cout << (ans == ool ? -1 : ans) << '\n'; }
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