답안 #58117

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
58117 2018-07-16T21:29:48 Z Benq 최솟값 배열 (IZhO11_hyper) C++14
0 / 100
514 ms 92636 KB
#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>

using namespace std;
using namespace __gnu_pbds;
 
typedef long long ll;
typedef long double ld;
typedef complex<ld> cd;

typedef pair<int, int> pi;
typedef pair<ll,ll> pl;
typedef pair<ld,ld> pd;

typedef vector<int> vi;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;
typedef vector<cd> vcd;

template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>;

#define FOR(i, a, b) for (int i=a; i<(b); i++)
#define F0R(i, a) for (int i=0; i<(a); i++)
#define FORd(i,a,b) for (int i = (b)-1; i >= a; i--)
#define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--)

#define sz(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define all(x) x.begin(), x.end()

const int MOD = 1000000007;
const ll INF = 1e18;
const int MX = 100001;

int N,M, X[34][34][34][34];

void solve(int d) {
    if (d == 3) {
        F0R(i,N) F0R(j,N) F0R(k,N) {
            deque<pi> d;
            F0Rd(l,N) {
                while (sz(d) && d.back().f >= X[i][j][k][l]) d.pop_back();
                d.pb({X[i][j][k][l],l});
                if (l <= N-M) {
                    while (d.front().s >= l+M) d.pop_front();
                    X[i][j][k][l] = d.front().f;
                }
            }
        }
    } else if (d == 2) {
        F0R(i,N) F0R(j,N) F0R(l,N-M+1) {
            deque<pi> d;
            F0Rd(k,N) {
                while (sz(d) && d.back().f >= X[i][j][k][l]) d.pop_back();
                d.pb({X[i][j][k][l],k});
                if (k <= N-M) {
                    while (d.front().s >= k+M) d.pop_front();
                    X[i][j][k][l] = d.front().f;
                }
            }
        }
    } else if (d == 1) {
    	F0R(i,N) F0R(k,N-M+1) F0R(l,N-M+1) {
            deque<pi> d;
            F0Rd(j,N) {
                while (sz(d) && d.back().f >= X[i][j][k][l]) d.pop_back();
                d.pb({X[i][j][k][l],j});
                if (j <= N-M) {
                    while (d.front().s >= j+M) d.pop_front();
                    X[i][j][k][l] = d.front().f;
                }
            }
        }
    } else {
    	F0R(j,N-M+1) F0R(k,N-M+1) F0R(l,N-M+1) {
            deque<pi> d;
            F0Rd(i,N) {
                while (sz(d) && d.back().f >= X[i][j][k][l]) d.pop_back();
                d.pb({X[i][j][k][l],i});
                if (i <= N-M) {
                    while (d.front().s >= i+M) d.pop_front();
                    X[i][j][k][l] = d.front().f;
                }
            }
        }
    }
}

int main() {
    ios_base::sync_with_stdio(0); cin.tie(0);
    cin >> N >> M;
    F0R(i,N) F0R(j,N) F0R(k,N) F0R(l,N) cin >> X[i][j][k][l];
    F0Rd(i,4) solve(i);
    F0R(i,N-M+1) F0R(j,N-M+1) F0R(k,N-M+1) F0R(l,N-M+1) cout << X[i][j][k][l] << " ";
}

/* Look for:
* the exact constraints (multiple sets are too slow for n=10^6 :( ) 
* special cases (n=1?)
* overflow (ll vs int?)
* array bounds
*/
# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 384 KB Output is correct
2 Correct 3 ms 748 KB Output is correct
3 Correct 7 ms 1392 KB Output is correct
4 Correct 7 ms 1500 KB Output is correct
5 Correct 9 ms 1608 KB Output is correct
6 Correct 20 ms 2796 KB Output is correct
7 Correct 17 ms 3184 KB Output is correct
8 Correct 39 ms 5564 KB Output is correct
9 Correct 58 ms 8916 KB Output is correct
10 Correct 41 ms 8916 KB Output is correct
11 Correct 104 ms 14740 KB Output is correct
12 Correct 259 ms 24840 KB Output is correct
13 Correct 168 ms 31920 KB Output is correct
14 Correct 297 ms 45792 KB Output is correct
15 Correct 514 ms 64432 KB Output is correct
16 Correct 208 ms 65260 KB Output is correct
17 Correct 252 ms 78800 KB Output is correct
18 Incorrect 223 ms 92636 KB Output isn't correct
19 Halted 0 ms 0 KB -