제출 #58103

#제출 시각아이디문제언어결과실행 시간메모리
58103Benq학교 설립 (IZhO13_school)C++14
100 / 100
177 ms26060 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/tree_policy.hpp> #include <ext/pb_ds/assoc_container.hpp> using namespace std; using namespace __gnu_pbds; typedef long long ll; typedef long double ld; typedef complex<ld> cd; typedef pair<int, int> pi; typedef pair<ll,ll> pl; typedef pair<ld,ld> pd; typedef vector<int> vi; typedef vector<ld> vd; typedef vector<ll> vl; typedef vector<pi> vpi; typedef vector<pl> vpl; typedef vector<cd> vcd; template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>; #define FOR(i, a, b) for (int i=a; i<(b); i++) #define F0R(i, a) for (int i=0; i<(a); i++) #define FORd(i,a,b) for (int i = (b)-1; i >= a; i--) #define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--) #define sz(x) (int)(x).size() #define mp make_pair #define pb push_back #define f first #define s second #define lb lower_bound #define ub upper_bound #define all(x) x.begin(), x.end() const int MOD = 1000000007; const ll INF = 1e18; const int MX = 300005; int N,M,S; ll ansS[MX], ansM[MX]; vpi v; int main() { ios_base::sync_with_stdio(0); cin.tie(0); cin >> N >> M >> S; F0R(i,N) { int A,B; cin >> A >> B; v.pb({A,B}); } sort(all(v),[](pi a, pi b){ return a.f-a.s < b.f-b.s; }); priority_queue<int,vi,greater<int>> pq; ll sum = 0; F0R(i,N) { pq.push(v[i].s); sum += v[i].s; if (sz(pq) > S) { sum -= pq.top(); pq.pop(); } ansS[i+1] = sum; } while (sz(pq)) pq.pop(); sum = 0; F0Rd(i,N) { pq.push(v[i].f); sum += v[i].f; if (sz(pq) > M) { sum -= pq.top(); pq.pop(); } ansM[i] = sum; } ll ans = 0; F0R(i,N+1) ans = max(ans,ansS[i]+ansM[i]); cout << ans; } /* Look for: * the exact constraints (multiple sets are too slow for n=10^6 :( ) * special cases (n=1?) * overflow (ll vs int?) * array bounds */
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