제출 #580546

#제출 시각아이디문제언어결과실행 시간메모리
580546talant117408Lottery (CEOI18_lot)C++17
100 / 100
1793 ms12288 KiB
#include <bits/stdc++.h>
 
using namespace std;
 
typedef long long ll;
typedef pair <int, int> pii;
typedef pair <ll, ll> pll;

#define long                unsigned long 
#define pb                  push_back
#define mp                  make_pair
#define all(v)              (v).begin(),(v).end()
#define rall(v)             (v).rbegin(),(v).rend()
#define lb                  lower_bound
#define ub                  upper_bound
#define sz(v)               int((v).size())
#define do_not_disturb      ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define endl                '\n'

void solve() {
    int n, l;
    cin >> n >> l;
    vector <int> v(n);
    for (auto &to : v) cin >> to;
    int q;
    cin >> q;
    vector <pii> queries(q);
    for (int i = 0; i < q; i++) {
        cin >> queries[i].first;
        queries[i].second = i;
    }
    sort(all(queries));
    
    vector <int> nxt(n+1);
    for (int i = 0; i <= n; i++) {
        auto it = lb(all(queries), mp(i, 0))-queries.begin();
        nxt[i] = it;
    }
    
    vector <vector <int>> dp(q+1, vector <int> (n));
    vector <vector <int>> partial(2, vector <int> (n));
    
    for (int j = 1; j < n-l+1; j++) {
        for (int k = 0; k < l; k++) {
            partial[0][j] += (v[k] != v[j+k]);
        }
        dp[nxt[partial[0][j]]][0]++;
        dp[nxt[partial[0][j]]][j]++;
    }
    
    for (int i = 1; i < n-l+1; i++) {
        fill(all(partial[i&1]), 0);
        for (int k = 0; k < l; k++) {
            partial[i&1][0] += (v[k] != v[i+k]);
        }
        for (int j = 1; j < n-l+1; j++) {
            if (i == j) continue;
            partial[i&1][j] = partial[(i&1)^1][j-1]-(v[i-1] != v[j-1])+(v[i+l-1] != v[j+l-1]);
        }
        for (int j = 0; j < n-l+1; j++) {
            if (i == j) continue;
            dp[nxt[partial[i&1][j]]][i]++;
            dp[nxt[partial[i&1][j]]][j]++;
        }
    }
    
    vector <vector <int>> ans(q, vector <int> (n));
    for (int i = 0; i < n-l+1; i++) for (int j = 1; j < q; j++) {
        dp[j][i] += dp[j-1][i];
    }
    for (int j = 0; j < q; j++) {
        ans[queries[j].second] = dp[j];
    }
    for (int j = 0; j < q; j++) {
        for (int i = 0; i < n-l+1; i++) {
            cout << ans[j][i]/2 << ' ';
        }
        cout << endl;
    }
}

int main() {
    do_not_disturb
    
    int t = 1;
    //~ cin >> t;
    while (t--) {
        solve();
    }
    
    return 0;
}
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