답안 #57935

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
57935 2018-07-16T14:14:06 Z red1108 구간 성분 (KOI15_interval) C++17
100 / 100
284 ms 1140 KB
#include <iostream>
#include <unordered_map>
#include <string>
#include <algorithm>
using namespace std;
unordered_map<char,int> prime;
string a, b;
int cnt[27],atop,btop,h[27];
struct DATA{
    int value;
    int s, e;
}ah[2500000],bh[2500000];
int asum[30][1600],bsum[30][1600];
bool cmp(DATA A, DATA B)
{
    return A.value<B.value;
}
void init()
{
    h[0]=1;
    h[1]=1;
    h[2]=1;
    h[3]=1;
    h[4]=2;
    h[5]=1;
    h[6]=2;
    h[7]=1;
    h[8]=2;
    h[9]=1;
    h[10]=1;
    h[11]=2;
    h[12]=2;
    h[13]=1;
    h[14]=1;
    h[15]=1;
    h[16]=1;
    h[17]=1;
    h[18]=2;
    h[19]=1;
    h[20]=1;
    h[21]=2;
    h[22]=2;
    h[23]=1;
    h[24]=2;
    h[25]=1;
}
int main()
{
    init();
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    int i, j,l,hashing,k,flag,x,get=0,kc;
    cin>>a;
    cin>>b;
    for(i=0;i<26;i++)
    {
        for(j=0;j<a.size();j++){asum[i][j]=a[j]-'a'==i?asum[i][j-1]+1:asum[i][j-1];}
    }
    for(i=0;i<26;i++)
    {
        for(j=0;j<b.size();j++){bsum[i][j]=b[j]-'a'==i?bsum[i][j-1]+1:bsum[i][j-1];}
    }
    l=min(a.size(),b.size());
    for(i=l;i>=1;i--)
    {
        hashing=0;
        atop=0;
        btop=0;
        for(j=0;j<i;j++) {hashing+=h[a[j]-'a'];}
        for(j=i-1;j<a.size();j++)
        {
            ah[++atop].value=hashing;
            ah[atop].s=j-i+1;
            ah[atop].e=j;
            hashing+=h[a[j+1]-'a'];
            hashing-=h[a[j-i+1]-'a'];
        }
        hashing=0;
        for(j=0;j<i;j++) {hashing+=h[b[j]-'a'];}
        for(j=i-1;j<b.size();j++)
        {
            bh[++btop].value=hashing;
            bh[btop].s=j-i+1;
            bh[btop].e=j;
            hashing+=h[b[j+1]-'a'];
            hashing-=h[b[j-i+1]-'a'];
        }
        sort(ah+1,ah+atop+1,cmp);
        sort(bh+1,bh+btop+1,cmp);
        k=1;
        for(j=1;j<=atop;j++)
        {
            while(bh[k].value<ah[j].value&&k<b.size()) k++;
            if(k>=b.size()) break;
            if(bh[k].value>ah[j].value) continue;
            kc=k;
            while(bh[k].value==ah[j].value&&k<b.size())
            {
                flag=1;
                for(x=0;x<26;x++)
                {
                    if(asum[x][ah[j].e]-asum[x][ah[j].s-1]!=bsum[x][bh[k].e]-bsum[x][bh[k].s-1]){flag=0;break;}
                }
                if(flag)
                {
                    get=1;
                    break;
                }
                k++;
            }
            if(get)
            {
                printf("%d\n", i);
                return 0;
            }
            if(ah[j].value==ah[j+1].value) k=kc;
        }
    }
    printf("0");
}

Compilation message

interval.cpp: In function 'int main()':
interval.cpp:57:18: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
         for(j=0;j<a.size();j++){asum[i][j]=a[j]-'a'==i?asum[i][j-1]+1:asum[i][j-1];}
                 ~^~~~~~~~~
interval.cpp:61:18: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
         for(j=0;j<b.size();j++){bsum[i][j]=b[j]-'a'==i?bsum[i][j-1]+1:bsum[i][j-1];}
                 ~^~~~~~~~~
interval.cpp:70:20: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
         for(j=i-1;j<a.size();j++)
                   ~^~~~~~~~~
interval.cpp:80:20: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
         for(j=i-1;j<b.size();j++)
                   ~^~~~~~~~~
interval.cpp:93:45: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
             while(bh[k].value<ah[j].value&&k<b.size()) k++;
                                            ~^~~~~~~~~
interval.cpp:94:17: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
             if(k>=b.size()) break;
                ~^~~~~~~~~~
interval.cpp:97:46: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
             while(bh[k].value==ah[j].value&&k<b.size())
                                             ~^~~~~~~~~
# 결과 실행 시간 메모리 Grader output
1 Correct 3 ms 632 KB Output is correct
2 Correct 3 ms 632 KB Output is correct
3 Correct 3 ms 800 KB Output is correct
4 Correct 5 ms 800 KB Output is correct
5 Correct 2 ms 800 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 25 ms 872 KB Output is correct
2 Correct 14 ms 872 KB Output is correct
3 Correct 3 ms 872 KB Output is correct
4 Correct 3 ms 872 KB Output is correct
5 Correct 31 ms 880 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 115 ms 976 KB Output is correct
2 Correct 123 ms 996 KB Output is correct
3 Correct 161 ms 1000 KB Output is correct
4 Correct 173 ms 1120 KB Output is correct
5 Correct 135 ms 1120 KB Output is correct
6 Correct 97 ms 1120 KB Output is correct
7 Correct 129 ms 1120 KB Output is correct
8 Correct 104 ms 1120 KB Output is correct
9 Correct 133 ms 1120 KB Output is correct
10 Correct 116 ms 1120 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 143 ms 1120 KB Output is correct
2 Correct 263 ms 1120 KB Output is correct
3 Correct 245 ms 1140 KB Output is correct
4 Correct 41 ms 1140 KB Output is correct
5 Correct 284 ms 1140 KB Output is correct