이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair <int, int> pii;
typedef pair <ll, ll> pll;
#define long unsigned long
#define pb push_back
#define mp make_pair
#define all(v) (v).begin(),(v).end()
#define rall(v) (v).rbegin(),(v).rend()
#define lb lower_bound
#define ub upper_bound
#define sz(v) int((v).size())
#define do_not_disturb ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define endl '\n'
const int N = 2e5+7;
vector <vector <int>> graph(N), new_graph(N);
int root, subtree[N];
ll ans;
void dfs(int v, int p) {
subtree[v] = (sz(new_graph[v]) == 1 ? 1 : 0);
for (auto to : new_graph[v]) {
if (to == p) {
continue;
}
dfs(to, v);
subtree[v] += subtree[to];
}
ans += 2 - (subtree[v] % 2);
}
int get(int n) {
ans = 0;
for (int i = 1; i <= n; i++) {
if (sz(new_graph[i]) > 1) {
root = i;
}
}
dfs(root, root);
if (subtree[root]&1) return -1;
else return ans-2;
}
void solve() {
int n, q;
cin >> n >> q;
for (int i = 1; i < n; i++) {
int a, b;
cin >> a >> b;
graph[a].pb(b);
graph[b].pb(a);
}
if (n <= 20000 && q <= 300) {
while (q--) {
int vertex = n+1;
int k;
cin >> k;
for (int i = 1; i <= n+k; i++) {
new_graph[i].clear();
for (auto to : graph[i]) new_graph[i].pb(to);
}
while (k--) {
int x;
cin >> x;
new_graph[x].pb(vertex);
new_graph[vertex].pb(x);
vertex++;
}
cout << get(vertex-1) << endl;
}
}
}
int main() {
do_not_disturb
int t = 1;
//~ cin >> t;
while (t--) {
solve();
}
return 0;
}
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