Submission #577290

#	Time	Username	Problem	Language	Result	Execution time	Memory
577290		MohammadAghil	Collecting Stamps 3 (JOI20_ho_t3)	C++17	0 / 100	1 ms	980 KiB

ho_t3

      #include <bits/stdc++.h>
//   #pragma GCC optimize ("Ofast,unroll-loops")
// #pragma GCC target ("avx2")
    using namespace std;
  typedef long long ll;
   typedef pair<ll, int> pp;
    #define er(args ...) cerr << __LINE__ << ": ", err(new istringstream(string(#args)), args), cerr << endl
      #define per(i,r,l) for(int i = (r); i >= (l); i--)
        #define rep(i,l,r) for(int i = (l); i < (r); i++)
           #define all(x) x.begin(), x.end()
              #define sz(x) (int)(x).size()
                  #define pb push_back
                      #define ss second
                           #define ff first
                                   void err(istringstream *iss){}template<typename T,typename ...Args> void err(istringstream *iss,const T &_val, const Args&...args){string _name;*iss>>_name;if(_name.back()==',')_name.pop_back();cerr<<_name<<" = "<<_val<<", ",err(iss,args...);}
template<typename T> bool chkmin(T &a, T b){return (b < a) ? a = b, 1 : 0;}
template<typename T> bool chkmax(T &a, T b){return (b > a) ? a = b, 1 : 0;}
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const ll mod = 1e9 + 7, maxn = 2e2 + 5, lg = 22, inf = ll(1e18) + 5;
ll pw(ll a,ll b,ll md=mod){if(!b)return 1;ll k=pw(a,b>>1ll);return k*k%md*(b&1ll?a:1)%md;}

ll dp[maxn][maxn][maxn<<1][2];

int main(){
     cin.tie(0) -> sync_with_stdio(0);
     int n, l; cin >> n >> l;
     vector<ll> x(n+1), t(n+1);
     rep(i,1,n+1) cin >> x[i];
     rep(i,1,n+1) cin >> t[i];
     vector<ll> xn(n+1), tn(n+1); 
     rep(i,1,n+1) xn[i] = l - x[n+1-i], tn[i] = t[n+1-i];
     
     int ans = 0;

     rep(i,0,n+1) rep(j,0,n+1) rep(k,0,(n<<1)+1) rep(t,0,2) dp[i][j][k][t] = inf;
     dp[0][0][0][0] = dp[0][0][0][1] = 0;

     rep(i,0,n+1){
          rep(j,0,n+1){
               rep(k,0,(n<<1)+1){

                    rep(t,0,2) if(dp[i][j][k][t] < inf) ans = max(ans, min(n, k));
                    // er(i, j, k);
                    if(i < n){
                         ll tm = dp[i][j][k][0] + xn[i+1] - xn[i];
                         chkmin(dp[i+1][j][k + (tm <= tn[i+1])][0], tm);
                         tm = dp[i][j][k][1] + x[j] + xn[i+1];
                         chkmin(dp[i+1][j][k + (tm <= tn[i+1])][0], tm);
                    }
                    if(j < n){
                         ll tm = dp[i][j][k][0] + xn[i] + x[j+1];
                         chkmin(dp[i][j+1][k + (tm <= t[j+1])][1], tm);
                         tm = dp[i][j][k][1] + x[j+1] - x[j];
                         chkmin(dp[i][j+1][k + (tm <= t[j+1])][1], tm);
                    }
               }
          }
     }

     cout << ans << '\n';
     return 0; 
}

• Subtask 1: 0 / 5
• Subtask 2: 0 / 10
• Subtask 3: 0 / 10
• Subtask 4: 0 / 75