제출 #57656

#제출 시각아이디문제언어결과실행 시간메모리
57656BenqThe Kingdom of JOIOI (JOI17_joioi)C++14
100 / 100
1330 ms18764 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/tree_policy.hpp> #include <ext/pb_ds/assoc_container.hpp> using namespace std; using namespace __gnu_pbds; typedef long long ll; typedef long double ld; typedef complex<ld> cd; typedef pair<int, int> pi; typedef pair<ll,ll> pl; typedef pair<ld,ld> pd; typedef vector<int> vi; typedef vector<ld> vd; typedef vector<ll> vl; typedef vector<pi> vpi; typedef vector<pl> vpl; typedef vector<cd> vcd; template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>; #define FOR(i, a, b) for (int i=a; i<(b); i++) #define F0R(i, a) for (int i=0; i<(a); i++) #define FORd(i,a,b) for (int i = (b)-1; i >= a; i--) #define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--) #define sz(x) (int)(x).size() #define mp make_pair #define pb push_back #define f first #define s second #define lb lower_bound #define ub upper_bound #define all(x) x.begin(), x.end() const int MOD = 1000000007; const ll INF = 1e18; const int MX = 100001; int H,W,g[2000][2000]; int l[2][2000], r[2][2000]; pi lo = {0,0}, hi = {0,0}; int L[2000], R[2000]; bool leftIncrease(int x) { F0R(i,H) { R[i] = r[x][i]; if (i) R[i] = max(R[i],R[i-1]); } F0Rd(i,H) { L[i] = l[x^1][i]; if (i < H-1) L[i] = min(L[i],L[i+1]); } F0R(i,H) if (R[i] >= L[i]) return 0; return 1; } bool leftDecrease(int x) { F0Rd(i,H) { R[i] = r[x][i]; if (i < H-1) R[i] = max(R[i],R[i+1]); } F0R(i,H) { L[i] = l[x^1][i]; if (i) L[i] = min(L[i],L[i-1]); } F0R(i,H) if (R[i] >= L[i]) return 0; return 1; } bool ok(int mid) { F0R(i,H) l[0][i] = l[1][i] = MOD, r[0][i] = r[1][i] = -MOD; F0R(i,H) F0R(j,W) { if (g[hi.f][hi.s]-g[i][j] > mid) r[0][i] = max(r[0][i],j), l[0][i] = min(l[0][i],j); if (g[i][j]-g[lo.f][lo.s] > mid) r[1][i] = max(r[1][i],j), l[1][i] = min(l[1][i],j); } return leftIncrease(0) || leftDecrease(0) || leftIncrease(1) || leftDecrease(1); } int main() { ios_base::sync_with_stdio(0); cin.tie(0); cin >> H >> W; F0R(i,H) F0R(j,W) { cin >> g[i][j]; if (g[i][j] < g[lo.f][lo.s]) lo = {i,j}; if (g[i][j] > g[hi.f][hi.s]) hi = {i,j}; } int lo = 0, hi = 1000000000; while (lo < hi) { int mid = (lo+hi)/2; if (ok(mid)) hi = mid; else lo = mid+1; } cout << lo; } /* Look for: * the exact constraints (multiple sets are too slow for n=10^6 :( ) * special cases (n=1?) * overflow (ll vs int?) * array bounds */
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...