제출 #576398

#제출 시각아이디문제언어결과실행 시간메모리
576398radal벽 칠하기 (APIO20_paint)C++17
63 / 100
1597 ms15748 KiB
#include <bits/stdc++.h>
#include "paint.h"
#pragma GCC target("sse,sse2,sse4,avx2")
#pragma GCC optimize("unroll-loops,O2")
#define rep(i,l,r) for (int i = l; i < r; i++)
#define repr(i,r,l) for (int i = r; i >= l; i--)
#define X first
#define Y second
#define all(x) (x).begin() , (x).end()
#define pb push_back
#define endl '\n'
#define debug(x) cerr << #x << " : " << x << endl;
using namespace std;
typedef long long ll;
typedef long double ld;
typedef pair<int,int> pll;
constexpr int N = 1e5+20,mod = 998244353,inf = 1e9+10;
inline int mkay(int a,int b){
    if (a+b >= mod) return a+b-mod;
//    if (a+b < 0) return a+b+mod;
    return a+b;
}
 
inline int poww(int a,int k){
    if (k < 0) return 0;
    int z = 1;
    while (k){
        if (k&1) z = 1ll*z*a%mod;
        a = 1ll*a*a%mod;
        k >>= 1;
    } 
    return z; 
}
vector<int> f[N],a,c;
vector<vector<int> > b;
int n,m,k;
inline bool check(int ind){
    if (ind+m-1 >= n) return 0;
    for (int i : f[c[ind]]){
        bool fl = 1;
        rep(j,ind+1,ind+m){
            i++;
            if (i == m) i = 0;
            int y = lower_bound(all(f[c[j]]),i)-f[c[j]].begin();
            if (y == (int)f[c[j]].size() || f[c[j]][y] != i){
                fl = 0;
                break;
            }
        }
        if (fl) return 1;
    }
    return 0;
}
inline int bs(int l,int r){
    int mid;
    while (r-l > 1){
        mid = (l+r) >> 1;
        if (check(mid)) l = mid;
        else{
            bool fl = 0;
            rep(j,0,1000){
                if (mid+j >= r) break;
                if (check(mid+j)){
                    l = mid+j;
                    fl = 1;
                    break;
                }
            }
            if (fl) continue;
            r = mid;
        }
    }
    return l;
}
int minimumInstructions(int nn,int mm,int kk,vector<int> C,vector<int> A,vector<vector<int>> B){
    n = nn;
    m = mm;
    k = kk;
    c = C;
    a = A;
    b = B;
    rep(i,0,m){
        for (int x : b[i])
            f[x].pb(i);
    }
    rep(i,0,n)
        if (f[c[i]].empty()) return -1;
    if (!check(0)) return -1;
    int cur = m,ans = 1;
    while (cur < n){
        bool fl = 0;
        int t = 100;
        rep(j,0,t){
            if (j == m) return -1;
            if (check(cur-j)){
                cur += (m-j);
                ans++;
                fl = 1;
                break;
            }
        }
        if (fl) continue;
        int x = bs(cur-m,cur-t+1);
        if (x == cur-m) return -1;
        cur = x+m;
        ans++;
    }
    return ans;
}
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...