이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair <int, int> pii;
typedef pair <ll, ll> pll;
#define long unsigned long
#define pb push_back
#define mp make_pair
#define all(v) (v).begin(),(v).end()
#define rall(v) (v).rbegin(),(v).rend()
#define lb lower_bound
#define ub upper_bound
#define sz(v) int((v).size())
#define do_not_disturb ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define endl '\n'
void solve() {
int n, q;
cin >> n >> q;
vector <int> v(n);
for (auto &to : v) cin >> to;
vector <pii> queries(q);
for (auto &to : queries) cin >> to.first >> to.second;
for (auto &to : queries) {
to.first--;
to.second--;
}
sort(all(v));
if (q == 1) {
vector <ll> ranges;
ll cnt = 1;
for (int i = 1; i < n; i++) {
if (v[i] == v[i-1]) cnt++;
else {
ranges.pb(cnt);
cnt = 1;
}
}
ranges.pb(cnt);
sort(rall(ranges));
ll ans = 0, sum = 0;
deque <ll> K;
for (auto to : ranges) {
if (sz(K)&1) {
K.push_back(to);
}
else {
K.push_front(to);
}
}
while (sz(K)) {
auto x = K.front(); K.pop_front();
ans += x*(x+1)/2 + sum*x + (n-sum-x)*x + sum*(n-sum-x);
sum += x;
}
cout << ans;
}
}
int main() {
do_not_disturb
int t = 1;
//~ cin >> t;
while (t--) {
solve();
}
return 0;
}
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