이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#pragma GCC target("avx")
#pragma GCC optimize("O3")
#pragma GCC optimize("Ofast")
//#pragma GCC target("popcnt")
//#pragma comment(linker, "/STACK:36777216")
#include <iostream>
#include <vector>
#include <algorithm>
#include <iomanip>
#include <tuple>
#include <math.h>
#include <set>
#include <stack>
#include <bitset>
#include <map>
#include <queue>
#include <random>
#include <array>
#include <unordered_set>
#include <cmath>
#include <cassert>
#include <unordered_map>
#define DEBUG
#define pqueue priority_queue
#define pb(x) push_back(x)
#define endl '\n'
#define all(x) x.begin(), x.end()
//#define int long long
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef vector<int> vi;
typedef vector<vector<int> > vvi;
typedef vector<ull> vull;
typedef vector<ll> vll;
// typedef tuple<ll, ll, ll> tiii;
typedef pair<int, int> pii;
typedef vector<pair<int, int> > vpii;
typedef pair<ll, ll> pll;
typedef vector<bool> vb;
typedef vector<string> vs;
typedef vector<vector<int> > vvi;
typedef vector<char> vc;
const ll inf = 1e9 + 228;
const ll infll = 1e18 + 228;
const ll mod = 1e9 + 7;
const ll mod3 = 1e9 + 7;
//static const int maxn = 1e6 + 228;
const ld eps = 1e-6;
const ll mod2 = 998244353;
const ld PI = atan2l(0, -1);
void fast_io() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
// freopen("input.txt", "r", stdin);
// freopen("lumber.out", "w", stdout);
}
const int maxn = 3e5 + 228;
int link[maxn];
int sz[maxn];
int lef[maxn];
int find(int v) {
if (link[v] == v)
return v;
return link[v] = find(link[v]);
}
void unite(int a, int b) {
a = find(a);
b = find(b);
if (a == b)
return;
if (sz[a] > sz[b])
swap(a, b);
sz[b] += sz[a];
link[a] = b;
lef[b] = min(lef[b], lef[a]);
}
bool cmp(pii a, pii b) {
if (a.first == b.first) {
return a.second > b.second;
} else {
return a.first < b.first;
}
}
int t[maxn * 4];
int get(int v, int l, int r, int ql, int qr) {
if (ql <= l && r <= qr) {
return t[v];
} else if (l > qr || ql > r) {
return 0;
} else {
int mid = (l + r) / 2;
return max(get(v * 2, l, mid, ql, qr), get(v * 2 + 1, mid + 1, r, ql, qr));
}
}
void upd(int v, int l, int r, int k, int k_new) {
if (l == r) {
t[v] = k_new;
} else {
int mid = (l + r) / 2;
if (k <= mid) {
upd(v * 2, l, mid, k, k_new);
} else {
upd(v * 2 + 1, mid + 1, r, k, k_new);
}
t[v] = max(t[v * 2], t[v * 2 + 1]);
}
}
void solve() {
for (int i = 0; i < maxn; i++) {
link[i] = i;
sz[i] = 1;
lef[i] = i;
}
int n, d;
cin >> n >> d;
vector<int> a(n);
for (int &i: a)
cin >> i;
vector<pii> kek;
for (int i = 0; i < n; i++) {
kek.pb(make_pair(a[i], i));
}
sort(all(kek), cmp);
set<int> lol;
vector<int> dp(n, 0);
for (pii i: kek) {
auto it = lol.lower_bound(i.second);
if (it != lol.end()) {
if (abs(i.second - *it) <= d)
unite(i.second, *it);
}
if (it != lol.begin()) {
it--;
if (abs(i.second - *it) <= d)
unite(i.second, *it);
}
int root = find(i.second);
int l = lef[root];
dp[i.second] = get(1, 0, maxn, max(l - d, 0), i.second - 1) + 1;
upd(1, 0, maxn, i.second, dp[i.second]);
}
cout << dp[n-1] << endl;
}
signed main() {
srand(time(NULL));
fast_io();
int q = 1;
// cin >> q;
while (q--) {
solve();
}
return 0;
}
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