이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<iostream>
#include<iomanip>
#include<algorithm>
#include<stack>
#include<queue>
#include<string>
#include<string.h>
#include<cmath>
#include<vector>
#include<map>
#include<unordered_map>
#include<set>
#include<unordered_set>
#include<cstdio>
#include<bitset>
#include<chrono>
#include<random>
#include<ext/rope>
/* ordered_set
#include<ext/pb_ds/assoc_container.hpp>
#include<ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
#define ordered_set tree<int, null_type,less<int>, rb_tree_tag,tree_order_statistics_node_update>
*/
#define int long long
#define pb push_back
#define fi first
#define se second
using namespace std;
using ll = long long;
using ld = long double;
using ull = unsigned long long;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const int maxN = 1e6 + 5;
const int mod = 1e9 + 7;
const ll oo = 1e18;
int n, x, a[maxN];
int b[maxN];
int f[maxN], e[maxN];
void ReadInput()
{
cin >> n >> x;
for(int i=1; i<=n; i++) cin >> a[i];
}
int Cal(int id)
{
for(int i=1; i<=n; i++)
{
if(i <= id) b[i] = a[i] - x;
else b[i] = a[i];
}
fill(e, e + n + 1, oo);
for(int i=1; i<=n; i++)
{
int j = lower_bound(e + 1, e + n + 1, b[i]) - e;
f[i] = j;
e[f[i]] = b[i];
}
return *max_element(f + 1, f + n + 1);
}
void Solve()
{
int res = 0;
for(int i=1; i<=n; i++)
{
res = max(res, Cal(i - 1));
}
cout << res;
}
int32_t main()
{
//freopen("x.inp", "r", stdin);
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
ReadInput();
Solve();
}
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