이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
// #pragma GCC optimize ("Ofast,unroll-loops")
// #pragma GCC target ("avx2")
using namespace std;
typedef long long ll;
typedef pair<int, int> pp;
#define er(args ...) cerr << __LINE__ << ": ", err(new istringstream(string(#args)), args), cerr << endl
#define per(i,r,l) for(int i = (r); i >= (l); i--)
#define rep(i,l,r) for(int i = (l); i < (r); i++)
#define all(x) x.begin(), x.end()
#define sz(x) (int)(x).size()
#define pb push_back
#define ss second
#define ff first
void err(istringstream *iss){}template<typename T,typename ...Args> void err(istringstream *iss,const T &_val, const Args&...args){string _name;*iss>>_name;if(_name.back()==',')_name.pop_back();cerr<<_name<<" = "<<_val<<", ",err(iss,args...);}
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const ll mod = 1e9 + 7, maxn = 1e5 + 1, maxk = 101, lg = 21, inf = ll(1e9) + 5;
ll pw(ll a,ll b,ll md=mod){if(!b)return 1;ll k=pw(a,b>>1ll);return k*k%md*(b&1ll?a:1)%md;}
int dp[maxn][maxk], a[maxn];
int main(){
cin.tie(0) -> sync_with_stdio(0);
int n, k; cin >> n >> k;
rep(i,1,n+1) cin >> a[i];
rep(i,1,n+1) dp[i][0] = inf;
rep(j,1,k+1){
vector<pp> stk{{j-1, dp[j-1][j-1]}};
rep(i,j,n+1){
int mn = inf;
while(sz(stk) && a[stk.back().ff] < a[i]){
mn = min(mn, stk.back().ss);
stk.pop_back();
}
dp[i][j] = mn + a[i];
if(sz(stk)) dp[i][j] = min(dp[i][j], dp[stk.back().ff][j]);
stk.pb({i, min(dp[i][j-1], mn)});
}
}
cout << dp[n][k] << '\n';
return 0;
}
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