이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "koala.h"
#include <bits/stdc++.h>
using namespace std;
const int MAXN=100;
int a[MAXN], b[MAXN];
int minValue(int N, int W) {
// TODO: Implement Subtask 1 solution here.
// You may leave this function unmodified if you are not attempting this
// subtask.
a[0]=1; for(int i=1; i<N; i++) a[i]=0;
playRound(a, b);
if(b[0]<=1) return 0;
else {
for(int i=0; i<N; i++) if(b[i]==0) return i;
}
return 0;
}
int maxValue(int N, int W) {
// TODO: Implement Subtask 2 solution here.
// You may leave this function unmodified if you are not attempting this
// subtask.
return 0;
}
int greaterValue(int N, int W) {
// TODO: Implement Subtask 3 solution here.
// You may leave this function unmodified if you are not attempting this
// subtask.
int n=N;
set<int> s;
while(s.size()!=7) s.insert((rand()%100)+1);
int aa=0, bb=0;
for(auto cur : s) {
a[0]=cur;
playRound(a, b);
for(int i=1; i<n; i++) aa+=b[i];
for(int i=1; i<n; i++) a[i]=0;
for(int i=1; i<n; i++) b[i]=0;
}
for(auto cur : s) {
a[1]=cur;
playRound(a, b);
for(int i=1; i<n; i++) bb+=b[i];
for(int i=1; i<n; i++) a[i]=0;
for(int i=1; i<n; i++) b[i]=0;
}
return aa<bb;
}
void allValues(int N, int W, int *P) {
if (W == 2*N) {
// TODO: Implement Subtask 4 solution here.
// You may leave this block unmodified if you are not attempting this
// subtask.
} else {
// TODO: Implement Subtask 5 solution here.
// You may leave this block unmodified if you are not attempting this
// subtask.
}
}
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