이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "books.h"
#include <bits/stdc++.h>
#ifndef EVAL
#include "grader.cpp"
#endif
using namespace std;
typedef long long ll;
typedef pair <int, int> pii;
typedef pair <ll, ll> pll;
#define pb push_back
#define mp make_pair
#define all(v) (v).begin(),(v).end()
#define sz(v) int((v).size())
#define do_not_disturb ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define endl '\n'
int mod = 1e9+7;
ll modulo(ll a) {
return ((a % mod) + mod) % mod;
}
ll add(ll a, ll b) {
return modulo(a + b);
}
ll mult(ll a, ll b) {
return modulo(a * b);
}
ll binpow(ll a, ll b) {
ll res = 1;
while (b) {
if (b&1) {
res = mult(res, a);
}
a = mult(a, a);
b >>= 1;
}
return res;
}
const int MX = 1e5+7;
ll val[MX];
ll ask(int i) {
if (val[i] > 0) return val[i];
val[i] = skim(i);
return val[i];
}
void solve(int n, int k, long long a, int s) {
int l = 1, r = n;
while (l < r) {
int mid = (l+r) >> 1;
if (a < ask(mid)) {
r = mid;
}
else {
l = mid+1;
}
}
int ind = l;
if (ask(ind) > 2*a) ind--;
if (ind < k) {
impossible();
return;
}
ll sum = 0;
for (int i = 1; i <= k; i++) {
sum += ask(i);
}
if (sum > a * 2) {
impossible();
return;
}
sum = 0;
for (int i = ind-k+1; i <= ind; i++) {
sum += ask(i);
}
if (sum < a) {
impossible();
return;
}
int ans = -1;
l = 1, r = n-k+1;
while (l <= r) {
int mid = (l+r) >> 1;
ll sum = 0;
for (int i = mid; i < mid+k; i++) {
sum += skim(i);
}
if (a <= sum && sum <= a*2) {
ans = mid;
break;
}
else if (sum < a) {
l = mid+1;
}
else {
r = mid-1;
}
}
if (ans == -1) impossible();
else {
vector <int> v;
for (int i = ans; i < ans+k; i++) {
v.pb(i);
}
answer(v);
}
}
/*
15 3 42 170
7 8 9 10 11 12 13 14 15 16 17 18 19 20 21
*/
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