Submission #573478

#	Time	Username	Problem	Language	Result	Execution time	Memory
573478		Vanilla	Parrots (IOI11_parrots)	C++17	98 / 100	11 ms	1364 KiB

encoder

#include <bits/stdc++.h>
#include "encoder.h"
#include "encoderlib.h"
using namespace std;

vector <int> mp[300];

void encode(int n, int m[]) {
    int ct = 0;
    for (int i1 = 0; i1 <= 4 && ct < 256; i1++)
		for (int i2 = i1; i2 <= 4 && ct < 256; i2++)
			for (int i3 = i2; i3 <= 4 && ct < 256; i3++)
				for (int i4 = i3; i4 <= 4 && ct < 256; i4++)
					for (int i5 = i4; i5 <= 4 && ct < 256; i5++)
						for (int i6 = i5; i6 <= 4 && ct < 256; i6++)
							for (int i7 = i6; i7 <= 4 && ct < 256; i7++){
                                vector <int> x = {i1, i2, i3, i4, i5, i6, i7};
                                mp[ct++] = x;
                            }

    
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < 7; j++){
            int v = i << 2;
            if (mp[m[i]][j] != 0) {
                v+=mp[m[i]][j] - 1;
                send(v);
            }
        }
    }
}

decoder

#include <bits/stdc++.h>
#include "decoder.h"
#include "decoderlib.h"
using namespace std;

vector <int> v[300];
map <vector <int>, int> revmp;

void decode(int n, int l, int x[]) {
    int ct = 0;
    for (int i1 = 0; i1 <= 4 && ct < 256; i1++)
		for (int i2 = i1; i2 <= 4 && ct < 256; i2++)
			for (int i3 = i2; i3 <= 4 && ct < 256; i3++)
				for (int i4 = i3; i4 <= 4 && ct < 256; i4++)
					for (int i5 = i4; i5 <= 4 && ct < 256; i5++)
						for (int i6 = i5; i6 <= 4 && ct < 256; i6++)
							for (int i7 = i6; i7 <= 4 && ct < 256; i7++){
								vector <int> x = {i1, i2, i3, i4, i5, i6, i7};
								revmp[x] = ct++;
							}
										
										
	
	for (int i = 0; i < n; i++){
		v[i].clear();
	}
	for (int i = 0; i < l; i++){
		int idx = x[i] >> 2;
		v[idx].push_back((x[i] & 3) + 1);
	}
	for (int i = 0; i < n; i++){
		while (v[i].size() != 7) v[i].push_back(0);
		sort(v[i].begin(), v[i].end());
		output(revmp[v[i]]);
	}
}

• Subtask 1: 17 / 17
• Subtask 2: 17 / 17
• Subtask 3: 18 / 18
• Subtask 4: 29 / 29
• Subtask 5: 17 / 19