이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "train.h"
#include <queue>
#include <algorithm>
#include <iostream>
#include <cassert>
using namespace std;
using VI = vector<int>;
using VVI = vector<VI>;
enum Player {
Arezou = 1, Borzou = 0
};
enum State {
UNKNOWN = -1, LOSING = 0, POSSIBLY_WINNING = 1
};
int N, M;
VVI G;
VI in_deg;
VI owner;
void bfs(int player, const VI& sources, vector<int>& states) {
queue<int> q;
for (int i : sources)
q.push(i);
VI num_neighbors_required(G.size());
for (int i = 0; i < N; i++) {
if (states[i] == UNKNOWN) {
if (owner[i] == player)
num_neighbors_required[i] = 1;
else
num_neighbors_required[i] = in_deg[i];
}
}
while (!q.empty()) {
int cur = q.front(); q.pop();
for (int nxt : G[cur]) {
if (states[nxt] != UNKNOWN)
continue;
num_neighbors_required[nxt]--;
if (num_neighbors_required[nxt] == 0) {
q.push(nxt);
states[nxt] = player == Arezou ? POSSIBLY_WINNING : LOSING;
}
}
}
}
std::vector<int> who_wins(std::vector<int> a, std::vector<int> r,
std::vector<int> u, std::vector<int> v)
{
owner = a;
N = a.size();
M = u.size();
assert( (int) v.size() == M );
// Build transpose graph G (that is, reverse each edge)
G = VVI(N);
in_deg = VI(N);
for (int j = 0; j < M; ++j) {
G[ v[j] ].push_back( u[j] );
in_deg[ u[j] ]++;
}
vector<int> states(N, UNKNOWN);
for (int ronda = 1; ronda <= 10000; ronda++) {
VI sources;
for (int i = 0; i < N; i++)
if (r[i] == 1 and states[i] != LOSING) {
sources.push_back(i);
states[i] = POSSIBLY_WINNING;
}
bfs(Arezou, sources, states);
/*
cerr << "Round #" << ronda << endl;
for (int i = 0; i < N; i++)
cerr << states[i] << ' ';
cerr << endl;
*/
if (count(states.begin(), states.end(), UNKNOWN) == 0)
break;
sources.clear();
for (int i = 0; i < N; i++) {
switch (states[i]) {
case UNKNOWN:
states[i] = LOSING;
case LOSING:
sources.push_back(i);
break;
case POSSIBLY_WINNING:
states[i] = UNKNOWN;
break;
}
}
bfs(Borzou, sources, states);
/*
for (int i = 0; i < N; i++)
cerr << states[i] << ' ';
cerr << endl;
*/
if (count(states.begin(), states.end(), UNKNOWN) == 0)
break;
}
VI res(N);
for (int i = 0; i < N; i++) {
assert( states[i] != UNKNOWN );
if (states[i] == LOSING)
res[i] = 0;
else
res[i] = 1;
}
return res;
}
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