제출 #571507

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
571507		zaneyu	카멜레온의 사랑 (JOI20_chameleon)	C++14	4 / 100	59 ms	24272 KiB

chameleon

#include "chameleon.h"
#include<bits/stdc++.h>
using namespace std;
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
typedef tree<long long,null_type,less_equal<long long>,rb_tree_tag,tree_order_statistics_node_update> indexed_set;
#pragma GCC optimize("Ofast")
//#pragma GCC target("avx2")
//order_of_key #of elements less than x
// find_by_order kth element
using ll=long long;
using ld=long double;
using pii=pair<int,int>;
#define f first
#define s second
#define pb push_back
#define REP(i,n) for(int i=0;i<n;i++)
#define REP1(i,n) for(int i=1;i<=n;i++)
#define FILL(n,x) memset(n,x,sizeof(n))
#define ALL(_a) _a.begin(),_a.end()
#define sz(x) (int)x.size()
#define SORT_UNIQUE(c) (sort(c.begin(),c.end()),c.resize(distance(c.begin(),unique(c.begin(),c.end()))))
const ll maxn=5e5+5;
const ll maxlg=__lg(maxn)+2;
const ll INF64=4e18;
const int INF=0x3f3f3f3f;
const int MOD=1e9+7;
const ld PI=acos(-1);
const ld eps=1e-6;
#define lowb(x) x&(-x)
#define MNTO(x,y) x=min(x,(__typeof__(x))y)
#define MXTO(x,y) x=max(x,(__typeof__(x))y)
template<typename T1,typename T2>
ostream& operator<<(ostream& out,pair<T1,T2> P){
    out<<P.f<<' '<<P.s;
    return out;
}
template<typename T>
ostream& operator<<(ostream& out,vector<T> V){
    REP(i,sz(V)) out<<V[i]<<((i!=sz(V)-1)?" ":"");
    return out;
}
namespace {
vector<int> vv[maxn];
bool hv(vector<int> v,int x){
    v.pb(x);
    return Query(v)!=sz(v);
}
}  // namespace
void Solve(int n) {
    vector<int> v[2];
    REP1(i,2*n){
        REP(j,2){
            vector<int> tmp=v[j];
            while(hv(v[j],i)){
                int l=0,r=sz(v[j])-1;
                while(l<r){
                    int mid=(l+r)/2;
                    vector<int> vv;
                    REP(k,mid+1) vv.pb(v[j][k]);
                    if(hv(vv,i)) r=mid;
                    else l=mid+1;
                }
                int x=v[j][l];
                vv[i].pb(x),vv[x].pb(i);
                v[j].erase(v[j].begin(),v[j].begin()+l+1);
            }
            v[j]=tmp;
        }
        if(hv(v[0],i)) v[1].pb(i);
        else v[0].pb(i);
    }
    //REP1(i,2*n) cout<<i<<' '<<vv[i]<<'\n';
    REP1(i,2*n){
        for(int x:vv[i]){
            assert(Query({i,x})==1);
            if(i>x) continue;
            vector<int> vv;
            REP1(k,2*n){
                if(k==i or k==x) continue;
                vv.pb(k);
            }
            if(Query(vv)<=n-1){
                Answer(i,x);
                break;
            } 
        }
    }
}

• Subtask 1: 4 / 4
• Subtask 2: 0 / 20
• Subtask 3: 0 / 20
• Subtask 4: 0 / 20
• Subtask 5: 0 / 36