제출 #57112

#제출 시각아이디문제언어결과실행 시간메모리
57112BenqTrading (IZhO13_trading)C++14
100 / 100
298 ms38520 KiB
#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>
 
using namespace std;
using namespace __gnu_pbds;
 
typedef long long ll;
typedef long double ld;
typedef complex<ld> cd;
 
typedef pair<int, int> pi;
typedef pair<ll,ll> pl;
typedef pair<ld,ld> pd;
 
typedef vector<int> vi;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;
typedef vector<cd> vcd;
 
template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>;
 
#define FOR(i, a, b) for (int i=a; i<(b); i++)
#define F0R(i, a) for (int i=0; i<(a); i++)
#define FORd(i,a,b) for (int i = (b)-1; i >= a; i--)
#define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--)
 
#define sz(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define all(x) x.begin(), x.end()
 
const int MOD = 1000000007;
const ll INF = 1e18;
const int MX = 300005;
 
int n,m;
priority_queue<pi> p;
vpi ad[MX];
 
int main() {
    ios_base::sync_with_stdio(0); cin.tie(0);
    cin >> n >> m;
    F0R(i,m) {
        int a,b,c; cin >> a >> b >> c;
        ad[a].pb({c-a,b});
    }
    FOR(i,1,n+1) {
        for (auto j: ad[i]) p.push(j);
        while (sz(p) && p.top().s < i) p.pop();
        if (sz(p)) cout << p.top().f+i << " ";
        else cout << 0 << " ";
    }
}
 
/* Look for:
* the exact constraints (multiple sets are too slow for n=10^6 :( ) 
* special cases (n=1?)
* overflow (ll vs int?)
* array bounds
*/
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