이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>
using namespace std;
using namespace __gnu_pbds;
typedef long long ll;
typedef long double ld;
typedef complex<ld> cd;
typedef pair<int, int> pi;
typedef pair<ll,ll> pl;
typedef pair<ld,ld> pd;
typedef vector<int> vi;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;
typedef vector<cd> vcd;
template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>;
#define FOR(i, a, b) for (int i=a; i<(b); i++)
#define F0R(i, a) for (int i=0; i<(a); i++)
#define FORd(i,a,b) for (int i = (b)-1; i >= a; i--)
#define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--)
#define sz(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define all(x) x.begin(), x.end()
const int MOD = 1000000007;
const ll INF = 1e18;
const int MX = 100005;
int N;
vector<array<int,3>> v;
ll sumG[MX], sumD[MX];
struct {
map<ll,int> m;
void ins(ll a, int b) {
auto it = m.lb(a);
if (it != m.end() && it->s >= b) return;
m[a] = b; it = m.find(a);
while (it != m.begin() && it->s >= prev(it)->s) m.erase(prev(it));
}
int query(ll x) {
auto it = m.lb(x);
if (it == m.end()) return -1;
return it->s;
// for all a >= x what is the max b
}
} con;
int main() {
ios_base::sync_with_stdio(0); cin.tie(0);
cin >> N; v.resize(N+1);
FOR(i,1,N+1) {
F0R(j,3) cin >> v[i][j];
sumG[i] = sumG[i-1]+v[i][1];
sumD[i] = sumD[i-1]+v[i][2];
}
ll ans = 0;
FORd(i,1,N+1) {
// sumD[j]-v[j][0] >= sumD[i-1]-v[i][0]
con.ins(sumD[i]-v[i][0],i);
int t = con.query(sumD[i-1]-v[i][0]);
ans = max(ans,sumG[t]-sumG[i-1]);
}
cout << ans;
}
/* Look for:
* the exact constraints (multiple sets are too slow for n=10^6 :( )
* special cases (n=1?)
* overflow (ll vs int?)
* array bounds
*/
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