제출 #57081

#제출 시각아이디문제언어결과실행 시간메모리
57081Benq회문 (APIO14_palindrome)C++14
100 / 100
104 ms45772 KiB

#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>

using namespace std;
using namespace __gnu_pbds;
 
typedef long long ll;
typedef long double ld;
typedef complex<ld> cd;

typedef pair<int, int> pi;
typedef pair<ll,ll> pl;
typedef pair<ld,ld> pd;

typedef vector<int> vi;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;
typedef vector<cd> vcd;

template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>;

#define FOR(i, a, b) for (int i=a; i<(b); i++)
#define F0R(i, a) for (int i=0; i<(a); i++)
#define FORd(i,a,b) for (int i = (b)-1; i >= a; i--)
#define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--)

#define sz(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define all(x) x.begin(), x.end()

const int MOD = 1000000007;
const ll INF = 1e18;
const int MX = 100001;

template<int SZ> struct palTree {
    static const int sigma = 26;
 
    int s[SZ], len[SZ], link[SZ], to[SZ][sigma], oc[SZ];
     
    int n, last, sz;
     
    palTree() {
        s[n++] = -1;
        link[0] = 1;
        len[1] = -1;
        sz = 2;
    }
     
    int get_link(int v) {
        while(s[n-len[v]-2] != s[n-1]) v = link[v];
        return v;
    }
     
    void add_letter(int c) {
        s[n++] = c;
        last = get_link(last);
        if (!to[last][c]) {
            len[sz] = len[last]+2;
            link[sz] = to[get_link(link[last])][c];
            to[last][c] = sz++;
        }
        last = to[last][c];
        // cout << "OH " << len[last] << " " << last << " " << n << "\n";
        oc[last] ++;
    }
    
    void prop() {
        vpi v;
        FOR(i,2,sz) v.pb({len[i],i});
        sort(all(v)); reverse(all(v));
        for (auto a: v) oc[link[a.s]] += oc[a.s]; 
    }
};

palTree<300010> p;

string s;

int main() {
    ios_base::sync_with_stdio(0); cin.tie(0);
    cin >> s;
    for (char c: s) p.add_letter(c-'a');
    p.prop();
    ll ans = 0;
    FOR(i,2,p.sz) ans = max(ans,(ll)p.len[i]*p.oc[i]);
    cout << ans;
}

/* Look for:
* the exact constraints (multiple sets are too slow for n=10^6 :( ) 
* special cases (n=1?)
* overflow (ll vs int?)
* array bounds
*/
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