oj.uz

답안 #570558

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
570558 2022-05-30T13:01:24 Z kwongweng Meetings 2 (JOI21_meetings2) C++17
0 / 100
 4 ms 7380 KB 
#include <bits/stdc++.h>
using namespace std;

/*
#pragma GCC target ("avx2")
#pragma GCC optimization ("Ofast")
#pragma GCC optimization ("unroll-loops")
*/
 
typedef long long ll;
typedef vector<int> vi;
typedef pair<int, int> ii;
typedef vector<ii> vii;
typedef long double ld;
typedef pair<ll, ll> pll;
#define FOR(i, a, b) for(int i = a; i < b; i++)
#define ROF(i, a, b) for(int i = a; i >= b; i--)
#define ms memset
#define pb push_back
#define fi first
#define se second
 
ll MOD = 1000000007;
ll MOD1 = 998244353;
 
ll power(ll base, ll n){
	if (n == 0) return 1;
	if (n == 1) return base;
	ll halfn = power(base, n/2);
	if (n % 2 == 0) return (halfn * halfn) % MOD;
	return (((halfn * halfn) % MOD) * base) % MOD;
}
 
ll inverse(ll n){
	return power(n, MOD-2);
}
 
ll add(ll a, ll b){
	return (a+b) % MOD;
}
 
ll mul(ll a, ll b){
	a %= MOD;
	return (a*b) % MOD;
}
 
ll gcd(ll a, ll b){
    if (a == 1) return 1;
    if (a == 0) return b;
    return gcd(b%a, a);
}

ld pi = 3.141592653589793238;
struct segtree{
	vector<ll> op, ans;
	int sz = 0;
	void init(int n){
		sz = n;
		op.assign(4*n, -1);
		ans.assign(4*n, 0);
	}
	void prop(int v, int tl, int tr){
		if (op[v] == -1 || tl == tr) return;
		int tm = (tl+tr)/2;
		op[2*v] = op[v];
		op[2*v+1] = op[v];
		ll len1 = tm-tl+1, len2 = tr-tm;
		ans[2*v] = op[v] * len1;
		ans[2*v+1] = op[v] * len2;
		op[v] = -1;
	}
	void update(int v, int tl, int tr, int l, int r, int val){
		prop(v, tl, tr);
		if (l > r) return;
		if (tl == l && tr == r){
			op[v] = val;
			ll len = tr-tl+1;
			ans[v] = val * len;
			return;
		}
		int tm = (tl+tr)/2;
		update(2*v, tl, tm, l, min(r,tm), val);
		update(2*v+1, tm+1, tr, max(l, tm+1), r, val);
		ans[v] = ans[2*v] + ans[2*v+1];
	}
	void update(int l, int r, int val){
		update(1, 0, sz-1, l, r, val);
	}
	ll get(int v, int tl, int tr, int l, int r){
		prop(v, tl, tr);
		if (l > r) return 0;
		if (tl == l && tr == r) return ans[v];
		int tm = (tl+tr)/2;
		ll m1 = get(2*v, tl, tm, l, min(r, tm));
		ll m2 = get(2*v+1, tm+1, tr, max(l, tm+1), r);
		return m1 + m2;
	}
	ll get(int l, int r){
		return get(1, 0, sz-1, l, r);
	}
};

const int N = 200001;
vi g[N], sz(N), ans(N), dist(N);

void dfs1(int u, int p){
	sz[u] = 1;
	for (int v : g[u]){
		if (v==p) continue;
		dist[v] = dist[u]+1;
		dfs1(v,u);
		sz[u]+=sz[v];
	}
}

void dfs2(int u, int p, int cur){
	int val = min(cur, sz[u]);
	ans[val*2] = max(ans[val*2], dist[u]+1);
	for (int v : g[u]){
		if (v==p) continue;
		dfs2(v,u,cur);
	}
}

void solve(){
    int n; cin >> n;
	FOR(i,0,n-1){
		int u, v; cin >> u >> v;
		g[u].pb(v);
		g[v].pb(u);
	}
	FOR(i,1,n+1){
		dfs1(i,0);
		for (int u : g[i]){
			dfs2(u,i,n-sz[u]);
		}
		FOR(j,1,n+1) dist[j] = 0;
	}
	ROF(i,n/2,1){
		ans[i*2] = max(ans[i*2], ans[(i+1)*2]);
	}
	FOR(i,1,n+1){
		if (i % 2 == 1) cout << 1 << '\n';
		else cout << ans[i] << '\n';
	}
}

int main(){
    cout << fixed << setprecision(8);
    ios::sync_with_stdio(false);
    if (fopen("input.txt", "r")) {
		freopen("input.txt", "r", stdin);
		freopen("output.txt", "w", stdout);
	}
    int TC = 1;
    //cin >> TC;
    FOR(i, 1, TC+1){
        //cout << "Case #" << i << ": ";
        solve();
    }
}

Compilation message

meetings2.cpp: In function 'int main()':
meetings2.cpp:152:10: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  152 |   freopen("input.txt", "r", stdin);
      |   ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~
meetings2.cpp:153:10: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  153 |   freopen("output.txt", "w", stdout);
      |   ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~

Subtask #1
0 / 4.0

# 결과 실행 시간 메모리 Grader output
1 Correct 4 ms 7380 KB Output is correct
2 Correct 4 ms 7380 KB Output is correct
3 Correct 4 ms 7380 KB Output is correct
4 Correct 4 ms 7380 KB Output is correct
5 Incorrect 4 ms 7380 KB Output isn't correct
6 Halted 0 ms 0 KB -

Subtask #2
0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Correct 4 ms 7380 KB Output is correct
2 Correct 4 ms 7380 KB Output is correct
3 Correct 4 ms 7380 KB Output is correct
4 Correct 4 ms 7380 KB Output is correct
5 Incorrect 4 ms 7380 KB Output isn't correct
6 Halted 0 ms 0 KB -

Subtask #3
0 / 80.0

# 결과 실행 시간 메모리 Grader output
1 Correct 4 ms 7380 KB Output is correct
2 Correct 4 ms 7380 KB Output is correct
3 Correct 4 ms 7380 KB Output is correct
4 Correct 4 ms 7380 KB Output is correct
5 Incorrect 4 ms 7380 KB Output isn't correct
6 Halted 0 ms 0 KB -