이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define PB push_back
#define ST first
#define ND second
//#pragma GCC optimize ("O3")
//#pragma GCC target("tune=native")
//mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
//#include <ext/pb_ds/assoc_container.hpp>
//#include <ext/pb_ds/tree_policy.hpp>
//using namespace __gnu_pbds;
//typedef tree<int, null_type, less_equal<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;
using namespace std;
using ll = long long;
using pi = pair<int, int>;
using vi = vector<int>;
const int nax = 100 * 1000 + 10;
int n, k;
vector<pi>G[nax];
ll dp[nax][2];
void dfs(int x, int p) {
ll sum = 0;
vector<ll>dx = {};
for(auto [nbh, w] : G[x]) if(nbh != p) {
dfs(nbh, x);
sum += dp[nbh][0];
if(-dp[nbh][0] + dp[nbh][1] + w > 0) dx.PB(-dp[nbh][0] + dp[nbh][1] + w);
}
sort(dx.rbegin(), dx.rend());
dp[x][0] = dp[x][1] = sum;
for(int i = 0; i < min(k - 1, (int)dx.size()); ++i) {
dp[x][1] += dx[i];
dp[x][0] += dx[i];
}
if((int)dx.size() >= k && k > 0) {
dp[x][0] += dx[k - 1];
}
}
vector<ll> minimum_closure_costs(int N, vi U, vi V, vi W) {
n = N;
ll sum = 0;
for(int i = 0; i < n - 1; ++i) {
G[U[i]].emplace_back(V[i], W[i]);
G[V[i]].emplace_back(U[i], W[i]);
sum += W[i];
}
vector<ll>res(n);
for(k = 0; k < n; ++k) {
dfs(0, -1);
res[k] = sum - dp[0][0];
}
return res;
}
//int main() {
//ios_base::sync_with_stdio(0);
//cin.tie(0);
//auto vec = minimum_closure_costs(4, {0, 2, 0}, {1, 0, 3}, {5, 10, 5});
//auto vec1 = minimum_closure_costs(5, {0, 0, 0, 2}, {1, 2, 3, 4}, {1, 4, 3, 2});
//cin >> n;
//vi u(n-1), v(n-1), w(n-1);
//for(int i = 0; i < n-1; ++i) cin >> u[i] >> v[i] >> w[i];
//auto vec = minimum_closure_costs(n, u, v, w);
//for(auto x : vec1) cout << x << " ";
//}
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