제출 #56952

#제출 시각아이디문제언어결과실행 시간메모리
56952Plurm수열 (APIO14_sequence)C++11
71 / 100
2050 ms105688 KiB
#pragma GCC optimize("Ofast") #include <cstdio> #include <vector> #include <algorithm> #include <stack> #define bad(x,y,z) ((C[y]-C[x])*(M[x]-M[z]) >= (C[z]-C[x])*(M[x]-M[y])) using namespace std; int a[131072]; long long dp[131072][2]; // End with i, having j parts; long long qs[131072]; int par[131072][256]; vector<int> M; vector<long long> C; vector<int> idx; inline void add(int i, int m, long long c){ M.push_back(m); C.push_back(c); idx.push_back(i); while(M.size() >= 3 && bad(M.size()-3, M.size()-2, M.size()-1)){ M.erase(M.end()-2); C.erase(C.end()-2); idx.erase(idx.end()-2); } } int ptr; inline int query(long long& x){ if(ptr >= M.size()) ptr = M.size()-1; while(ptr < M.size()-1 && M[ptr+1]*x + C[ptr+1] > M[ptr]*x + C[ptr]) ptr++; return ptr; } inline int fastscan(){ int x = 0; int c = getchar(); while(c < 48 || c >= 58) c = getchar(); while(c >= 48 && c < 58){ x *= 10; x += c-48; c = getchar(); } return x; } int main(){ int n,k; n = fastscan(); k = fastscan(); k++; add(0,0,0); for(int i = 1; i <= n; i++){ a[i] = fastscan(); qs[i] = qs[i-1] + (long long)a[i]; dp[i][0] = -1e16; } for(int j = 1; j <= k; j++){ if(j > 1) add(j-1,qs[j-1], dp[j-1][(j+1) % 2] - qs[j-1]*qs[j-1]); for(int i = j; i <= n; i++){ int id = query(qs[i]); par[i][j] = idx[id]; dp[i][j % 2] = M[id]*qs[i] + C[id]; add(i,qs[i], dp[i][(j+1) % 2] - qs[i]*qs[i]); } M.clear(); C.clear(); idx.clear(); ptr = 0; } printf("%lld\n",dp[n][k % 2]); int x = n; stack<int> stk; for(int j = k; j > 1; j--){ x = par[x][j]; stk.push(x); } while(!stk.empty()){ printf("%d ",stk.top()); stk.pop(); } }

컴파일 시 표준 에러 (stderr) 메시지

sequence.cpp: In function 'int query(long long int&)':
sequence.cpp:27:9: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
  if(ptr >= M.size()) ptr = M.size()-1;
     ~~~~^~~~~~~~~~~
sequence.cpp:28:12: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
  while(ptr < M.size()-1 && M[ptr+1]*x + C[ptr+1] > M[ptr]*x + C[ptr]) ptr++;
        ~~~~^~~~~~~~~~~~
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